Questions: Fill in the missing values to make the equations true. (a) log2 11 + log2 5 = log2 □ (b) log3 □ - log3 4 = log3 7/4 (c) log9 32 = □ log9 2

Fill in the missing values to make the equations true.
(a) log2 11 + log2 5 = log2 □
(b) log3 □ - log3 4 = log3 7/4
(c) log9 32 = □ log9 2
Transcript text: Fill in the missing values to make the equations true. (a) $\log _{2} 11+\log _{2} 5=\log _{2}$ $\square$ (b) $\log _{3}$ $\square$ $-\log _{3} 4=\log _{3} \frac{7}{4}$ (c) $\log _{9} 32=$ $\square$ $\log _{9} 2$
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Solution

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Solution Steps

Step 1: Solve part (a) using logarithm addition rule

The logarithm addition rule states that \( \log_b a + \log_b c = \log_b (a \cdot c) \).
Apply this rule to part (a):
\[ \log_2 11 + \log_2 5 = \log_2 (11 \cdot 5) = \log_2 55. \] Thus, the missing value is \( 55 \).


Step 2: Solve part (b) using logarithm subtraction rule

The logarithm subtraction rule states that \( \log_b a - \log_b c = \log_b \left( \frac{a}{c} \right) \).
Apply this rule to part (b):
\[ \log_3 x - \log_3 4 = \log_3 \left( \frac{x}{4} \right). \] Set this equal to \( \log_3 \frac{7}{4} \):
\[ \log_3 \left( \frac{x}{4} \right) = \log_3 \frac{7}{4}. \] Since the logarithms are equal, their arguments must be equal:
\[ \frac{x}{4} = \frac{7}{4}. \] Solve for \( x \):
\[ x = 7. \] Thus, the missing value is \( 7 \).


Step 3: Solve part (c) using logarithm power rule

The logarithm power rule states that \( \log_b a^k = k \log_b a \).
Rewrite \( \log_9 32 \) in terms of \( \log_9 2 \):
\[ \log_9 32 = \log_9 (2^5) = 5 \log_9 2. \] Thus, the missing value is \( 5 \).

Final Answer

(a) \( \boxed{55} \)
(b) \( \boxed{7} \)
(c) \( \boxed{5} \)

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