Questions: Practice Problems 1. Write the sum or difference in the standard form a+bi without using a calculator. a. (2-3 i)+(6+5 i) b. (2+i)-(9 i-3)

Practice Problems
1. Write the sum or difference in the standard form a+bi without using a calculator.
a. (2-3 i)+(6+5 i)
b. (2+i)-(9 i-3)
Transcript text: Practice Problems 1. Write the sum or difference in the standard form $a+b i$ without using a calculator. a. $(2-3 i)+(6+5 i)$ b. $(2+i)-(9 i-3)$
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Solution

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Solution Steps

To solve these problems, we need to perform basic arithmetic operations on complex numbers. For each part, we will add or subtract the real parts and the imaginary parts separately.

Part (a)
  1. Add the real parts: \(2 + 6\)
  2. Add the imaginary parts: \(-3i + 5i\)
Part (b)
  1. Subtract the real parts: \(2 - (-3)\)
  2. Subtract the imaginary parts: \(i - 9i\)
Step 1: Add the Real Parts for Part (a)

To find the sum of the real parts in part (a), we calculate: \[ 2 + 6 = 8 \]

Step 2: Add the Imaginary Parts for Part (a)

To find the sum of the imaginary parts in part (a), we calculate: \[ -3i + 5i = 2i \]

Step 3: Combine the Results for Part (a)

Combining the real and imaginary parts, we get: \[ (2 - 3i) + (6 + 5i) = 8 + 2i \]

Step 4: Subtract the Real Parts for Part (b)

To find the difference of the real parts in part (b), we calculate: \[ 2 - (-3) = 2 + 3 = 5 \]

Step 5: Subtract the Imaginary Parts for Part (b)

To find the difference of the imaginary parts in part (b), we calculate: \[ i - 9i = 1i - 9i = -8i \]

Step 6: Combine the Results for Part (b)

Combining the real and imaginary parts, we get: \[ (2 + i) - (9i - 3) = 5 - 8i \]

Final Answer

For part (a): \[ \boxed{8 + 2i} \]

For part (b): \[ \boxed{5 - 8i} \]

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