Questions: Using the given data, find the following.
28 23 9 3 16
Part: 0 / 2
Part 1 of 2
Identify the five-number summary. Round your answers to one decimal place as needed.
Low =
Q1= , MD = , Q3= , High =
Transcript text: Using the given data, find the following.
\[
\begin{array}{lllll}
28 & 23 & 9 & 3 & 16
\end{array}
\]
Part: $0 / 2$
Part 1 of 2
Identify the five-number summary. Round your answers to one decimal place as needed.
Low $=$ $\square$
$\square$ $Q_{1}=$ , MD = $\square$ , $Q_{3}=$ $\square$ , High = $\square$
Solution
Solution Steps
Step 1: Sort the Data
The given data is \( [28, 23, 9, 3, 16] \). After sorting, we obtain:
\[
\text{Sorted data} = [3, 9, 16, 23, 28]
\]
Step 2: Calculate the Five-Number Summary
The five-number summary consists of the following components:
Low: The minimum value in the sorted data, which is:
\[
\text{Low} = 3
\]
High: The maximum value in the sorted data, which is:
\[
\text{High} = 28
\]
Step 3: Calculate \( Q_1 \) (First Quartile)
To find \( Q_1 \), we use the formula for the rank:
\[
\text{Rank} = Q \times (N + 1) = 0.25 \times (5 + 1) = 1.5
\]
Since the rank is \( 1.5 \), we average the values at positions 1 and 2:
\[
Q_1 = \frac{X_{\text{lower}} + X_{\text{upper}}}{2} = \frac{3 + 9}{2} = 6.0
\]
Step 4: Calculate the Median (\( Q_2 \))
To find the median, we use the formula for the rank:
\[
\text{Rank} = Q \times (N + 1) = 0.5 \times (5 + 1) = 3.0
\]
The median corresponds to the value at position 3:
\[
\text{Median} = 16
\]
Step 5: Calculate \( Q_3 \) (Third Quartile)
To find \( Q_3 \), we use the formula for the rank:
\[
\text{Rank} = Q \times (N + 1) = 0.75 \times (5 + 1) = 4.5
\]
Since the rank is \( 4.5 \), we average the values at positions 4 and 5:
\[
Q_3 = \frac{X_{\text{lower}} + X_{\text{upper}}}{2} = \frac{23 + 28}{2} = 25.5
\]
Final Answer
The five-number summary is:
Low = \( 3 \)
\( Q_1 = 6.0 \)
Median = \( 16 \)
\( Q_3 = 25.5 \)
High = \( 28 \)
Thus, the final answer is:
\[
\boxed{\text{Low} = 3, \, Q_1 = 6.0, \, \text{Median} = 16, \, Q_3 = 25.5, \, \text{High} = 28}
\]