To find the wavelength of a neutron, we use the de Broglie wavelength formula:
\[ \lambda = \frac{h}{mv} \]
where:
Substitute the given values into the de Broglie wavelength formula:
\[ \lambda = \frac{6.626 \times 10^{-34}}{(1.67 \times 10^{-27}) \times (2.65 \times 10^5)} \]
Calculate the denominator:
\[ (1.67 \times 10^{-27}) \times (2.65 \times 10^5) = 4.4255 \times 10^{-22} \]
Now, calculate the wavelength:
\[ \lambda = \frac{6.626 \times 10^{-34}}{4.4255 \times 10^{-22}} = 1.497 \times 10^{-12} \, \text{m} \]
The wavelength of the neutron is:
\[ \boxed{1.497 \times 10^{-12} \, \text{m}} \]
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