Questions: Complete the table below. For example, in the first row decide whether Sc^3+ is a cation or anion. In the second row, write the symbol for the ion that an atom sulfur is mostly likely to form and then decide what type of ion it is. element most likely ion --- --- --- symbol of ion type of ion scandium Sc^3+ cation anion sulfur cation anion iodine cation anion cesium cation anion barium cation anion

Complete the table below. For example, in the first row decide whether Sc^3+ is a cation or anion. In the second row, write the symbol for the ion that an atom sulfur is mostly likely to form and then decide what type of ion it is.

element  most likely ion
---  ---  ---
  symbol of ion  type of ion
scandium  Sc^3+  cation anion
sulfur    cation anion
iodine    cation anion
cesium    cation anion
barium    cation anion
Transcript text: Complete the table below. For example, in the first row decide whether $\mathrm{Sc}^{3+}$ is a cation or anion. In the second row, write the symbol for the ion that an atc sulfur is mostly likely to form and then decide what type of ion it is. \begin{tabular}{|c|c|c|} \hline \multirow{2}{*}{ element } & \multicolumn{2}{|l|}{ most likely ion } \\ \hline & \begin{tabular}{l} symbol of \\ ion \end{tabular} & type of ion \\ \hline scandium & $\mathrm{Sc}^{3+}$ & cation anion \\ \hline sulfur & $\square$ & O cation anion \\ \hline iodine & $\square$ & cation anion \\ \hline cesium & $\square$ & cation anion \\ \hline barium & $\square$ & cation anion \\ \hline \end{tabular}
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Solution

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Solution Steps

Step 1: Determine the Ion for Scandium

Scandium (\(\mathrm{Sc}\)) forms a \(3+\) ion, denoted as \(\mathrm{Sc}^{3+}\). This is a cation because it has a positive charge.

Step 2: Determine the Ion for Sulfur

Sulfur (\(\mathrm{S}\)) typically gains two electrons to achieve a stable electron configuration, forming the ion \(\mathrm{S}^{2-}\). This is an anion because it has a negative charge.

Step 3: Determine the Ion for Iodine

Iodine (\(\mathrm{I}\)) typically gains one electron to form the ion \(\mathrm{I}^{-}\). This is an anion because it has a negative charge.

Final Answer

\[ \begin{array}{|c|c|c|} \hline \text{element} & \text{symbol of ion} & \text{type of ion} \\ \hline \text{scandium} & \mathrm{Sc}^{3+} & \text{cation} \\ \hline \text{sulfur} & \mathrm{S}^{2-} & \text{anion} \\ \hline \text{iodine} & \mathrm{I}^{-} & \text{anion} \\ \hline \end{array} \]

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