Questions: In the molecule below, identify and circle a bond made up of overlapping sp^2-sp^3 atomic orbitals (AO) and identify and square a different bond made up of sp^3 - sp AO overlap. Explain your answer for both the sp^3-sp and s^2-s^3 bonds.

In the molecule below, identify and circle a bond made up of overlapping sp^2-sp^3 atomic orbitals (AO) and identify and square a different bond made up of sp^3 - sp AO overlap. Explain your answer for both the sp^3-sp and s^2-s^3 bonds.

Transcript text: In the molecule below, identify and circle a bond made up of overlapping $\mathrm{sp}^{2}-\mathrm{sp}^{3}$ atomic orbitals (AO) and identify and square a different bond made up of $\mathrm{sp}^{3}$ - sp AO overlap. Explain your answer for both the $s p^{3}-s p$ and $s^{2}-s^{3}$ bonds.

Solution

Solution Steps

Step 1: Identify sp2-sp3 Bond

In the given molecule, identify the atoms involved in sp2 and sp3 hybridization.
The carbonyl carbon (C=O) is sp2 hybridized, and the adjacent nitrogen (N) is sp3 hybridized.
The bond between the carbonyl carbon (C=O) and the nitrogen (N) is an sp2-sp3 bond.

Step 2: Identify sp3-sp Bond

Identify the atoms involved in sp3 and sp hybridization.
The nitrogen (N) adjacent to the carbonyl carbon is sp3 hybridized, and the carbon (C) in the carbonyl group is sp hybridized.
The bond between the nitrogen (N) and the carbon (C) in the carbonyl group is an sp3-sp bond.

Step 3: Circle and Square the Bonds

Circle the bond between the carbonyl carbon (C=O) and the nitrogen (N) to indicate the sp2-sp3 bond.
Square the bond between the nitrogen (N) and the carbon (C) in the carbonyl group to indicate the sp3-sp bond.

Final Answer

The bond between the carbonyl carbon (C=O) and the nitrogen (N) is an sp2-sp3 bond (circled).
The bond between the nitrogen (N) and the carbon (C) in the carbonyl group is an sp3-sp bond (squared).

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