Questions: In the molecule below, identify and circle a bond made up of overlapping sp^2-sp^3 atomic orbitals (AO) and identify and square a different bond made up of sp^3 - sp AO overlap. Explain your answer for both the sp^3-sp and s^2-s^3 bonds.

In the molecule below, identify and circle a bond made up of overlapping sp^2-sp^3 atomic orbitals (AO) and identify and square a different bond made up of sp^3 - sp AO overlap. Explain your answer for both the sp^3-sp and s^2-s^3 bonds.
Transcript text: In the molecule below, identify and circle a bond made up of overlapping $\mathrm{sp}^{2}-\mathrm{sp}^{3}$ atomic orbitals (AO) and identify and square a different bond made up of $\mathrm{sp}^{3}$ - sp AO overlap. Explain your answer for both the $s p^{3}-s p$ and $s^{2}-s^{3}$ bonds.
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Solution

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Solution Steps

Step 1: Identify sp2-sp3 Bond
  • In the given molecule, identify the atoms involved in sp2 and sp3 hybridization.
  • The carbonyl carbon (C=O) is sp2 hybridized, and the adjacent nitrogen (N) is sp3 hybridized.
  • The bond between the carbonyl carbon (C=O) and the nitrogen (N) is an sp2-sp3 bond.
Step 2: Identify sp3-sp Bond
  • Identify the atoms involved in sp3 and sp hybridization.
  • The nitrogen (N) adjacent to the carbonyl carbon is sp3 hybridized, and the carbon (C) in the carbonyl group is sp hybridized.
  • The bond between the nitrogen (N) and the carbon (C) in the carbonyl group is an sp3-sp bond.
Step 3: Circle and Square the Bonds
  • Circle the bond between the carbonyl carbon (C=O) and the nitrogen (N) to indicate the sp2-sp3 bond.
  • Square the bond between the nitrogen (N) and the carbon (C) in the carbonyl group to indicate the sp3-sp bond.

Final Answer

  • The bond between the carbonyl carbon (C=O) and the nitrogen (N) is an sp2-sp3 bond (circled).
  • The bond between the nitrogen (N) and the carbon (C) in the carbonyl group is an sp3-sp bond (squared).
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