Questions: Solve by completing the square and applying the square root property. Express the solution set in exact s c^2 + 16c - 4 = 0 The solution set is .

Solve by completing the square and applying the square root property. Express the solution set in exact s

c^2 + 16c - 4 = 0

The solution set is .
Transcript text: Solve by completing the square and applying the square root property. Express the solution set in exact s \[ c^{2}+16 c-4=0 \] The solution set is $\square$ $\}$.
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Solution

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Solution Steps

Step 1: Completing the Square

To solve the equation \( c^2 + 16c - 4 = 0 \) by completing the square, we first isolate the constant term on one side:

\[ c^2 + 16c = 4 \]

Next, we take half of the coefficient of \( c \) (which is 16), square it, and add it to both sides. Half of 16 is 8, and squaring it gives us 64:

\[ c^2 + 16c + 64 = 4 + 64 \]

This simplifies to:

\[ (c + 8)^2 = 68 \]

Step 2: Applying the Square Root Property

Now, we apply the square root property to solve for \( c \):

\[ c + 8 = \pm \sqrt{68} \]

Subtracting 8 from both sides gives us:

\[ c = -8 \pm \sqrt{68} \]

Step 3: Simplifying the Square Root

The square root \( \sqrt{68} \) can be simplified:

\[ \sqrt{68} = \sqrt{4 \cdot 17} = 2\sqrt{17} \]

Thus, we can express \( c \) as:

\[ c = -8 \pm 2\sqrt{17} \]

Final Answer

The solution set is:

\[ \boxed{c = -8 + 2\sqrt{17}, \; c = -8 - 2\sqrt{17}} \]

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