Questions: Given: CD bisects AE, AB CD angle E congruent to angle BCA Prove: triangle ABC congruent to triangle CDE

Given: CD bisects AE, AB  CD
angle E congruent to angle BCA

Prove: triangle ABC congruent to triangle CDE
Transcript text: Given: $\overline{C D}$ bisects $\overline{A E}, \overline{A B} \| \overline{C D}$ \[ \angle E \cong \angle B C A \] Prove: $\triangle A B C \cong \triangle C D E$
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Solution

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Write a paragraph proof.

Given: \(\overline{C D}\) bisects \(\overline{A E}\), \(\overline{A B} \parallel \overline{C D}\) \(\angle E \cong \angle B C A\)

Prove: \(\triangle A B C \cong \triangle C D E\)

Step Subtitle

We are given that \(\overline{C D}\) bisects \(\overline{A E}\). This means that \(\overline{A C} \cong \overline{C E}\). We are also given that \(\overline{A B} \parallel \overline{C D}\). Because of this, \(\angle B A C \cong \angle D C E\) since they are alternate interior angles. Finally, we are given that \(\angle E \cong \angle B C A\). Therefore, by Angle-Side-Angle (ASA) Congruence, we can conclude that \(\triangle A B C \cong \triangle C D E\).

\(\triangle ABC \cong \triangle CDE\) by ASA.

\(\triangle ABC \cong \triangle CDE\) by ASA.

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