Questions: Given: CD bisects AE, AB CD
angle E congruent to angle BCA
Prove: triangle ABC congruent to triangle CDE
Transcript text: Given: $\overline{C D}$ bisects $\overline{A E}, \overline{A B} \| \overline{C D}$
\[
\angle E \cong \angle B C A
\]
Prove: $\triangle A B C \cong \triangle C D E$
Solution
Write a paragraph proof.
Given: \(\overline{C D}\) bisects \(\overline{A E}\), \(\overline{A B} \parallel \overline{C D}\)
\(\angle E \cong \angle B C A\)
Prove: \(\triangle A B C \cong \triangle C D E\)
Step Subtitle
We are given that \(\overline{C D}\) bisects \(\overline{A E}\). This means that \(\overline{A C} \cong \overline{C E}\). We are also given that \(\overline{A B} \parallel \overline{C D}\). Because of this, \(\angle B A C \cong \angle D C E\) since they are alternate interior angles. Finally, we are given that \(\angle E \cong \angle B C A\). Therefore, by Angle-Side-Angle (ASA) Congruence, we can conclude that \(\triangle A B C \cong \triangle C D E\).