Questions: Sixty-four percent of adults in a certain country believe that life on other planets is plausible. You randomly select five adults and ask them whether they believe that life on other planets is plausible. The random variable represents the number of adults who believe that life on other planets is plausible. Find the mean, variance, and standard deviation of the binomial distribution for the random variable interpret the results Find the mean of the binomial distribution μ= (Round to two decimal places as needed.)

Sixty-four percent of adults in a certain country believe that life on other planets is plausible. You randomly select five adults and ask them whether they believe that life on other planets is plausible. The random variable represents the number of adults who believe that life on other planets is plausible. Find the mean, variance, and standard deviation of the binomial distribution for the random variable interpret the results

Find the mean of the binomial distribution μ= (Round to two decimal places as needed.)
Transcript text: Sixty-four percent of adults in a certain country believe that life on other planets is plausible. You randomly select five adults and ask them whether they believe that life on other planets is plausible. The random variable represents the number of adults who believe that life on other planets is plausible. Find the mean, variance, and standard deviation of the binomial distribution for the random variable interpret the results Find the mean of the binomial distribution $\mu=\square$ (Round to two decimal places as needed.)
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Solution

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Solution Steps

Step 1: Calculate the Mean

The mean \( \mu \) of a binomial distribution can be calculated using the formula:

\[ \mu = n \cdot p \]

where:

  • \( n = 5 \) (the number of trials),
  • \( p = 0.64 \) (the probability of success).

Substituting the values:

\[ \mu = 5 \cdot 0.64 = 3.2 \]

Step 2: Calculate the Variance

The variance \( \sigma^2 \) of a binomial distribution is given by the formula:

\[ \sigma^2 = n \cdot p \cdot q \]

where:

  • \( q = 1 - p = 0.36 \) (the probability of failure).

Substituting the values:

\[ \sigma^2 = 5 \cdot 0.64 \cdot 0.36 = 1.15 \]

Step 3: Calculate the Standard Deviation

The standard deviation \( \sigma \) is the square root of the variance:

\[ \sigma = \sqrt{n \cdot p \cdot q} \]

Substituting the values:

\[ \sigma = \sqrt{5 \cdot 0.64 \cdot 0.36} \approx 1.07 \]

Final Answer

The results of the analysis are as follows:

  • Mean (Expected Value): \( \mu = 3.2 \)
  • Variance: \( \sigma^2 = 1.15 \)
  • Standard Deviation: \( \sigma \approx 1.07 \)

Thus, the final boxed answers are:

\[ \boxed{\mu = 3.2} \] \[ \boxed{\sigma^2 = 1.15} \] \[ \boxed{\sigma \approx 1.07} \]

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