Questions: If f(x) = (3 x^2 tan x) / (sec x) find f'(x). Find f'(1).

If
f(x) = (3 x^2 tan x) / (sec x)
find f'(x).
Find f'(1).
Transcript text: Score: $0 / 1$ Scoring Method: Best Answer If \[ f(x)=\frac{3 x^{2} \tan x}{\sec x} \] find $f^{\prime}(x)$. $\square$ Find $f^{\prime}(1)$. $\square$ Submit $\square$ Reset
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Solution

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Solution Steps

To find the derivative \( f'(x) \) of the function \( f(x) = \frac{3x^2 \tan x}{\sec x} \), we can simplify the function first and then apply the quotient rule or product rule as needed. After finding the derivative, we can substitute \( x = 1 \) to find \( f'(1) \).

Step 1: Simplifying the Function

We start with the function \[ f(x) = \frac{3x^2 \tan x}{\sec x}. \] Using the identity \(\sec x = \frac{1}{\cos x}\), we can rewrite the function as \[ f(x) = 3x^2 \tan x \cdot \cos x = 3x^2 \sin x. \]

Step 2: Finding the Derivative

Next, we differentiate \(f(x)\) with respect to \(x\): \[ f'(x) = \frac{d}{dx}(3x^2 \sin x). \] Using the product rule, we find: \[ f'(x) = 3x^2 \cos x + 6x \sin x. \]

Step 3: Evaluating the Derivative at \(x = 1\)

Now, we substitute \(x = 1\) into the derivative: \[ f'(1) = 3 \cos(1) + 6 \sin(1). \] Calculating the values, we have: \[ f'(1) \approx 3 \cdot 0.5403 + 6 \cdot 0.8415 \approx 1.6209 + 5.0490 \approx 6.6699. \]

Final Answer

Thus, the derivative \(f'(x)\) is \[ f'(x) = 3x^2 \cos x + 6x \sin x, \] and the value of \(f'(1)\) is approximately \[ \boxed{6.6700}. \]

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