To find the derivative \( f'(x) \) of the function \( f(x) = \frac{3x^2 \tan x}{\sec x} \), we can simplify the function first and then apply the quotient rule or product rule as needed. After finding the derivative, we can substitute \( x = 1 \) to find \( f'(1) \).
Step 1: Simplifying the Function
We start with the function
\[
f(x) = \frac{3x^2 \tan x}{\sec x}.
\]
Using the identity \(\sec x = \frac{1}{\cos x}\), we can rewrite the function as
\[
f(x) = 3x^2 \tan x \cdot \cos x = 3x^2 \sin x.
\]
Step 2: Finding the Derivative
Next, we differentiate \(f(x)\) with respect to \(x\):
\[
f'(x) = \frac{d}{dx}(3x^2 \sin x).
\]
Using the product rule, we find:
\[
f'(x) = 3x^2 \cos x + 6x \sin x.
\]
Step 3: Evaluating the Derivative at \(x = 1\)
Now, we substitute \(x = 1\) into the derivative:
\[
f'(1) = 3 \cos(1) + 6 \sin(1).
\]
Calculating the values, we have:
\[
f'(1) \approx 3 \cdot 0.5403 + 6 \cdot 0.8415 \approx 1.6209 + 5.0490 \approx 6.6699.
\]
Final Answer
Thus, the derivative \(f'(x)\) is
\[
f'(x) = 3x^2 \cos x + 6x \sin x,
\]
and the value of \(f'(1)\) is approximately
\[
\boxed{6.6700}.
\]