Questions: Select from the dropdown menu above the table to review the number of moles of each element in the flask containing one mole each of CH4, NH3, H2 S, and CO2 added to 55.5 moles of water. What is the maximum number of moles of glycine (C2 H5 NO2) that could be made in the flask if no other molecules were made? 1 mole of glycine 2 moles of glycine 5 moles of glycine 120 moles of glycine Submit Request Answer

Select from the dropdown menu above the table to review the number of moles of each element in the flask containing one mole each of CH4, NH3, H2 S, and CO2 added to 55.5 moles of water. What is the maximum number of moles of glycine (C2 H5 NO2) that could be made in the flask if no other molecules were made?

1 mole of glycine

2 moles of glycine

5 moles of glycine

120 moles of glycine

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Transcript text: Select from the dropdown menu above the table to review the number of moles of each element in the flask containing one mole each of $\mathrm{CH}_{4}, \mathrm{NH}_{3}, \mathrm{H}_{2} \mathrm{~S}$, and $\mathrm{CO}_{2}$ added to 55.5 moles of water. What is the maximum number of moles of glycine $\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NO}_{2}\right)$ that could be made in the flask if no other molecules were made? 1 mole of glycine 2 moles of glycine 5 moles of glycine 120 moles of glycine Submit Request Answer

Solution

Solution Steps

Step 1: Determine the Composition of Glycine

Glycine has the chemical formula $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NO}_{2}$. This means each mole of glycine contains:

2 moles of Carbon (C)
5 moles of Hydrogen (H)
1 mole of Nitrogen (N)
2 moles of Oxygen (O)

Step 2: Calculate the Available Moles of Each Element

From the table, the total moles of each element available in the flask are:

Carbon (C): 2 moles
Hydrogen (H): 120 moles
Oxygen (O): 58 moles
Nitrogen (N): 1 mole
Sulfur (S): 1 mole (not needed for glycine)

Step 3: Determine the Limiting Element

To find the maximum number of moles of glycine that can be formed, we need to determine which element is the limiting factor. We calculate the maximum possible moles of glycine based on each element:

For Carbon: $\frac{2 \text{ moles of C}}{2 \text{ moles of C per glycine}} = 1 \text{ mole of glycine}$
For Hydrogen: $\frac{120 \text{ moles of H}}{5 \text{ moles of H per glycine}} = 24 \text{ moles of glycine}$
For Oxygen: $\frac{58 \text{ moles of O}}{2 \text{ moles of O per glycine}} = 29 \text{ moles of glycine}$
For Nitrogen: $\frac{1 \text{ mole of N}}{1 \text{ mole of N per glycine}} = 1 \text{ mole of glycine}$

The limiting element is Nitrogen, which allows for only 1 mole of glycine to be formed.