Questions: Write a balanced chemical equation for the reaction of gaseous nitrogen dioxide with hydrogen gas to form gaseous ammonia and liquid water.
Express your answer as a chemical equation. Identify all of the phases in your answer.
Transcript text: Write a balanced chemical equation for the reaction of gaseous nitrogen dioxide with hydrogen gas to form gaseous ammonia and liquid water.
Express your answer as a chemical equation. Identify all of the phases in your answer.
Solution
Solution Steps
Step 1: Identify the Reactants and Products
The reactants in this chemical reaction are nitrogen dioxide (\(\text{NO}_2\)) and hydrogen gas (\(\text{H}_2\)). The products are ammonia (\(\text{NH}_3\)) and water (\(\text{H}_2\text{O}\)).
Step 2: Write the Unbalanced Chemical Equation
Write the chemical equation with the reactants and products, including their phases:
\[
\text{NO}_2(g) + \text{H}_2(g) \rightarrow \text{NH}_3(g) + \text{H}_2\text{O}(l)
\]
Step 3: Balance the Chemical Equation
To balance the equation, ensure that the number of atoms of each element is the same on both sides of the equation.
Nitrogen (N): There is 1 nitrogen atom in \(\text{NO}_2\) and 1 in \(\text{NH}_3\). To balance, we need 2 \(\text{NO}_2\) molecules to provide 2 nitrogen atoms for 2 \(\text{NH}_3\) molecules.
Hydrogen (H): There are 2 hydrogen atoms in \(\text{H}_2\) and 3 in \(\text{NH}_3\). To balance, we need 3 \(\text{H}_2\) molecules to provide 6 hydrogen atoms for 2 \(\text{NH}_3\) and 3 \(\text{H}_2\text{O}\) molecules.
Oxygen (O): There are 2 oxygen atoms in \(\text{NO}_2\) and 1 in \(\text{H}_2\text{O}\). To balance, we need 3 \(\text{H}_2\text{O}\) molecules to use up the 3 oxygen atoms from 2 \(\text{NO}_2\) molecules.
The balanced equation is:
\[
2\text{NO}_2(g) + 7\text{H}_2(g) \rightarrow 2\text{NH}_3(g) + 4\text{H}_2\text{O}(l)
\]
Final Answer
The balanced chemical equation for the reaction is:
\[
\boxed{2\text{NO}_2(g) + 7\text{H}_2(g) \rightarrow 2\text{NH}_3(g) + 4\text{H}_2\text{O}(l)}
\]