Questions: 7. What output will you get with this code? List 1=[x**3 if x % 2=0 else x for x in range (1,11) print(List1) A: [1,8,3,64,5,216,7,512,9,1000] B: [1,6,3,12,5,18,7,24,9,30] C: [1,2,27,4,125,6,343,8,729,10] D: [1,8,3,64,5,216,7,512,9,1000,11] 8. What is the output of the following code? import numpy as np a= np.array ([20,5,13,12]) print( a - (np.sum(a) / np.min(a) - a[1]) ) A: [30,15,23,22] B: [15,0,8,7] C: [12,-3,5,4]

Let's address the questions one by one.

What output will you get with this code?

List1 = [x**3 if x % 2 == 0 else x for x in range(1, 11)]
print(List1)

Options: A: \([1, 8, 3, 64, 5, 216, 7, 512, 9, 1000]\)
B: \([1, 6, 3, 12, 5, 18, 7, 24, 9, 30]\)
C: \([1, 2, 27, 4, 125, 6, 343, 8, 729, 10]\)
D: \([1, 8, 3, 64, 5, 216, 7, 512, 9, 1000, 11]\)

Answer: The answer is A: \([1, 8, 3, 64, 5, 216, 7, 512, 9, 1000]\)

Explanation:

• The list comprehension iterates over the range from 1 to 10 (inclusive).
• For each \( x \), if \( x \% 2 == 0 \) (i.e., \( x \) is even), it computes \( x^3 \).
• If \( x \) is odd, it simply includes \( x \) in the list.

So, the output list will be:

• \( 1 \) (odd)
• \( 8 \) (2^3)
• \( 3 \) (odd)
• \( 64 \) (4^3)
• \( 5 \) (odd)
• \( 216 \) (6^3)
• \( 7 \) (odd)
• \( 512 \) (8^3)
• \( 9 \) (odd)
• \( 1000 \) (10^3)

What is the output of the following code?

import numpy as np
a = np.array([20, 5, 13, 12])
print(a - (np.sum(a) / np.min(a) - a[1]))

Options: A: \([30, 15, 23.22]\)
B: \([15, 0, 8, 7.7]\)
C: \([12, -3, 5, 4]\)

Answer: The answer is B: \([15, 0, 8, 7.7]\)

Explanation:

• a is a numpy array: \([20, 5, 13, 12]\).
• np.sum(a) calculates the sum of the array: \(20 + 5 + 13 + 12 = 50\).
• np.min(a) finds the minimum value in the array: \(5\).
• a[1] is the second element of the array: \(5\).

Now, compute the expression inside the print statement: \[ \text{np.sum(a)} / \text{np.min(a)} - a[1] = 50 / 5 - 5 = 10 - 5 = 5 \]

So, the expression simplifies to: \[ a - 5 \]

Subtracting 5 from each element in the array: \[ [20 - 5, 5 - 5, 13 - 5, 12 - 5] = [15, 0, 8, 7] \]

Therefore, the output is: \[ [15, 0, 8, 7] \]

However, there seems to be a slight discrepancy in the options provided. The closest match is B: \([15, 0, 8, 7.7]\), but the correct output should be \([15, 0, 8, 7]\). This might be a typo in the options.