Questions: Ohm's law is often written in the form I=E/R where I is the current in amperes (A), E is the voltage, and R is the resistance in ohms. What is the voltage necessary to push a 0.80 -A current through a resistance of 430 ohms?

Ohm's law is often written in the form I=E/R where I is the current in amperes (A), E is the voltage, and R is the resistance in ohms. What is the voltage necessary to push a 0.80 -A current through a resistance of 430 ohms?

Transcript text: Ohm's law is often written in the form $I=\frac{E}{R}$ where $I$ is the current in amperes $(A), E$ is the voltage, and $R$ is the resistance in ohms. What is the voltage necessary to push a 0.80 -A current through a resistance of 430 ohms?

Solution

Solution Steps

Step 1: Identify the Given Values

We are given the current $ I = 0.80 $ A and the resistance $ R = 430 $ ohms.

Step 2: Use Ohm's Law

Ohm's Law is given by the formula: \[ I = \frac{E}{R} \] We need to solve for the voltage $ E $. Rearrange the formula to solve for $ E $: \[ E = I \times R \]

Step 3: Substitute the Given Values

Substitute the given values of $ I $ and $ R $ into the equation: \[ E = 0.80 \, \text{A} \times 430 \, \Omega \]

Step 4: Calculate the Voltage

Perform the multiplication to find the voltage: \[ E = 0.80 \times 430 = 344 \, \text{V} \]