Questions: Classify each chemical compound: compound type of compound PbCrO4 ◯ ionic ◯ molecular H2S ionic ◯ molecular Cl2O3 ionic ◯ molecular

Transcript text: Classify each chemical compound: compound | type of compound $\mathrm{PbCrO}_{4}$ | $\bigcirc$ ionic & $\bigcirc$ molecular $\mathrm{H}_{2} \mathrm{~S}$ | ionic & $\bigcirc$ molecular $\mathrm{Cl}_{2} \mathrm{O}_{3}$ | ionic & $\bigcirc$ molecular

Solution

Solution Steps

Step 1: Understanding Ionic and Molecular Compounds

Ionic compounds are formed when metals transfer electrons to non-metals, resulting in a lattice of positive and negative ions. Molecular compounds, on the other hand, are formed when non-metals share electrons, resulting in discrete molecules.

Step 2: Classifying $\mathrm{PbCrO}_{4}$

$\mathrm{PbCrO}_{4}$ is composed of lead (Pb), a metal, and the polyatomic ion $\mathrm{CrO}_{4}^{2-}$. Since it involves a metal and a polyatomic ion, it is classified as an ionic compound.

Step 3: Classifying $\mathrm{H}_{2}\mathrm{~S}$

$\mathrm{H}_{2}\mathrm{~S}$ is composed of hydrogen and sulfur, both of which are non-metals. The compound is formed by sharing electrons, making it a molecular compound.

Step 4: Classifying $\mathrm{Cl}_{2}\mathrm{O}_{3}$

$\mathrm{Cl}_{2}\mathrm{O}_{3}$ is composed of chlorine and oxygen, both of which are non-metals. This compound is formed by sharing electrons, classifying it as a molecular compound.

Final Answer

\[ \begin{array}{|c|cc|} \hline \text{compound} & \text{type of compound} \\ \hline \mathrm{PbCrO}_{4} & \boxed{\text{ionic}} \\ \hline \mathrm{H}_{2} \mathrm{~S} & \boxed{\text{molecular}} \\ \hline \mathrm{Cl}_{2} \mathrm{O}_{3} & \boxed{\text{molecular}} \\ \hline \end{array} \]

Was this solution helpful?

Unhelpful

Helpful

Questions asked by other users

< Previous Next >

Thank you for your feedback.

Copied!