Questions: 310 points If the initial velocity of a car is 8.46 meters per second and its final velocity is 9544 meters per second, what is its acceleration in meters per second squared if it takes 1.94 sec to make this change? Round your answer to two decimal places. Type your answer

Solution Steps

We are given the following values:

• Initial velocity, \( v_i = 8.46 \, \text{m/s} \)
• Final velocity, \( v_f = 9544 \, \text{m/s} \)
• Time taken, \( t = 1.94 \, \text{s} \)

The formula for acceleration \( a \) is given by: \[ a = \frac{v_f - v_i}{t} \]

Substitute the given values into the formula: \[ a = \frac{9544 \, \text{m/s} - 8.46 \, \text{m/s}}{1.94 \, \text{s}} \]

Calculate the numerator: \[ 9544 - 8.46 = 9535.54 \] Now, divide by the time: \[ a = \frac{9535.54}{1.94} \approx 4915.25 \, \text{m/s}^2 \]

Final Answer