Questions: Calculating Conservation of Energy
A 6.1 kg brick falls from a roof. At 3.0 s, t brick reaches the ground at 0 m .
What is the potential energy of the brick?
Ep=[?] J
Ep=m g h
For gravitational acceleration, use g=10 m / s^2.
0 J
300 J
610 J
Transcript text: Calculating Conservation of Energy
A 6.1 kg brick falls from a roof. At $3.0 \mathrm{~s}, \mathrm{t}$ brick reaches the ground at 0 m .
What is the potential energy of the brick?
\[
\begin{array}{c}
E_{p}=[?] \mathrm{J} \\
E_{p}=m g h
\end{array}
\]
For gravitational acceleration, use $g=10 \mathrm{~m} / \mathrm{s}^{2}$.
0 J
300 J
610 J
Solution
Solution Steps
Step 1: Identify the Given Values
We are given the following values:
Mass of the brick, \( m = 6.1 \, \text{kg} \)
Gravitational acceleration, \( g = 10 \, \text{m/s}^2 \)
The brick reaches the ground, so the height, \( h = 0 \, \text{m} \)
Step 2: Understand the Formula for Potential Energy
The potential energy \( E_p \) of an object at a height \( h \) is given by the formula:
\[
E_p = mgh
\]
Step 3: Calculate the Potential Energy
Substitute the given values into the formula:
\[
E_p = 6.1 \, \text{kg} \times 10 \, \text{m/s}^2 \times 0 \, \text{m} = 0 \, \text{J}
\]
Final Answer
The potential energy of the brick when it reaches the ground is \(\boxed{0 \, \text{J}}\).