Questions: Calculating Conservation of Energy A 6.1 kg brick falls from a roof. At 3.0 s, t brick reaches the ground at 0 m . What is the potential energy of the brick? Ep=[?] J Ep=m g h For gravitational acceleration, use g=10 m / s^2. 0 J 300 J 610 J

Calculating Conservation of Energy

A 6.1 kg brick falls from a roof. At 3.0 s, t brick reaches the ground at 0 m .
What is the potential energy of the brick?

Ep=[?] J 
Ep=m g h

For gravitational acceleration, use g=10 m / s^2.
0 J

300 J

610 J
Transcript text: Calculating Conservation of Energy A 6.1 kg brick falls from a roof. At $3.0 \mathrm{~s}, \mathrm{t}$ brick reaches the ground at 0 m . What is the potential energy of the brick? \[ \begin{array}{c} E_{p}=[?] \mathrm{J} \\ E_{p}=m g h \end{array} \] For gravitational acceleration, use $g=10 \mathrm{~m} / \mathrm{s}^{2}$. 0 J 300 J 610 J
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Solution

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Solution Steps

Step 1: Identify the Given Values

We are given the following values:

  • Mass of the brick, \( m = 6.1 \, \text{kg} \)
  • Gravitational acceleration, \( g = 10 \, \text{m/s}^2 \)
  • The brick reaches the ground, so the height, \( h = 0 \, \text{m} \)
Step 2: Understand the Formula for Potential Energy

The potential energy \( E_p \) of an object at a height \( h \) is given by the formula: \[ E_p = mgh \]

Step 3: Calculate the Potential Energy

Substitute the given values into the formula: \[ E_p = 6.1 \, \text{kg} \times 10 \, \text{m/s}^2 \times 0 \, \text{m} = 0 \, \text{J} \]

Final Answer

The potential energy of the brick when it reaches the ground is \(\boxed{0 \, \text{J}}\).

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