Questions: How many moles of KCl are present in 95.3 mL of 210 M KCl?

Transcript text: How many moles of KCl are present in 95.3 mL of 210 M KCl?

Solution

Solution Steps

Step 1: Identify the given values

We are given:

Volume of KCl solution: \( 95.3 \, \text{mL} \)
Molarity of KCl solution: \( 210 \, \text{M} \)

Step 2: Convert volume from mL to L

To use the molarity formula, we need the volume in liters: \[ 95.3 \, \text{mL} = 0.0953 \, \text{L} \]

Step 3: Use the molarity formula to find moles

The molarity formula is: \[ \text{Molarity} = \frac{\text{moles of solute}}{\text{liters of solution}} \] Rearranging to solve for moles of solute: \[ \text{moles of KCl} = \text{Molarity} \times \text{Volume in liters} \] \[ \text{moles of KCl} = 210 \, \text{M} \times 0.0953 \, \text{L} \]

Step 4: Calculate the moles of KCl

\[ \text{moles of KCl} = 210 \times 0.0953 = 20.013 \]