Questions: Solve the absolute value equation. 3a+4=4a-2 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The solution set is . (Type an integer or a simplified fraction. Use a comma to separate answers as needed.) B. The solution set is ∅.

Solve the absolute value equation.
3a+4=4a-2

Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. The solution set is   .
(Type an integer or a simplified fraction. Use a comma to separate answers as needed.)
B. The solution set is ∅.
Transcript text: Solve the absolute value equation. \[ |3 a+4|=|4 a-2| \] Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The solution set is $\square$ \} . (Type an integer or a simplified fraction. Use a comma to separate answers as needed.) B. The solution set is $\varnothing$.
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Solution

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Solution Steps

To solve the absolute value equation \(|3a + 4| = |4a - 2|\), we need to consider the different cases where the expressions inside the absolute values are equal or opposite. This leads to two main cases to solve: \(3a + 4 = 4a - 2\) and \(3a + 4 = -(4a - 2)\). We then solve these linear equations separately and check if the solutions satisfy the original equation.

Step 1: Set Up the Equation

We start with the absolute value equation: \[ |3a + 4| = |4a - 2| \]

Step 2: Consider the Cases

To solve this, we consider two cases:

  1. \(3a + 4 = 4a - 2\)
  2. \(3a + 4 = -(4a - 2)\)
Step 3: Solve Case 1

For the first case: \[ 3a + 4 = 4a - 2 \] Subtract \(3a\) from both sides: \[ 4 = a - 2 \] Add 2 to both sides: \[ a = 6 \]

Step 4: Solve Case 2

For the second case: \[ 3a + 4 = -(4a - 2) \] Distribute the negative sign: \[ 3a + 4 = -4a + 2 \] Add \(4a\) to both sides: \[ 7a + 4 = 2 \] Subtract 4 from both sides: \[ 7a = -2 \] Divide by 7: \[ a = -\frac{2}{7} \]

Step 5: Combine the Solutions

The solutions from both cases are: \[ a = 6 \quad \text{and} \quad a = -\frac{2}{7} \]

Final Answer

\[ \boxed{a = 6, -\frac{2}{7}} \]

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