Questions: During one shift, the express lane clerk recorded how many times customers violated the "10 items or less" rule for his lane. In particular, he recorded how many items over the limit each violator placed on the conveyor belt. This data is summarized in the histogram below. NOTE: The last class actually represents "7 or more items," not just 7 items. What is the frequency of times the limit was exceeded by less than 6 items? Answer: times

During one shift, the express lane clerk recorded how many times customers violated the "10 items or less" rule for his lane. In particular, he recorded how many items over the limit each violator placed on the conveyor belt. This data is summarized in the histogram below. NOTE: The last class actually represents "7 or more items," not just 7 items.

What is the frequency of times the limit was exceeded by less than 6 items?

Answer: times
Transcript text: During one shift, the express lane clerk recorded how many times customers violated the "10 items or less" rule for his lane. In particular, he recorded how many items over the limit each violator placed on the conveyor belt. This data is summarized in the histogram below. NOTE: The last class actually represents "7 or more items," not just 7 items. What is the frequency of times the limit was exceeded by less than 6 items? Answer: $\square$ times
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Solution

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Solution Steps

Step 1: Understand the Problem

The problem asks for the frequency of times the limit was exceeded by less than 6 items, based on the histogram provided.

Step 2: Analyze the Histogram

The histogram shows the frequency of times customers exceeded the "10 items or less" rule by different amounts. The x-axis represents the number of items over 10, and the y-axis represents the frequency.

Step 3: Identify Relevant Data

We need to sum the frequencies for the bins that represent exceeding the limit by less than 6 items. These bins are:

  • 0.5 to 1.5
  • 1.5 to 2.5
  • 2.5 to 3.5
  • 3.5 to 4.5
  • 4.5 to 5.5
Step 4: Sum the Frequencies

From the histogram:

  • 0.5 to 1.5: Frequency = 8
  • 1.5 to 2.5: Frequency = 12
  • 2.5 to 3.5: Frequency = 10
  • 3.5 to 4.5: Frequency = 9
  • 4.5 to 5.5: Frequency = 7

Sum these frequencies: \[ 8 + 12 + 10 + 9 + 7 = 46 \]

Final Answer

The frequency of times the limit was exceeded by less than 6 items is 46 times.

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