Questions: Choose the graph of y=sec x. Answer (a) and (b). (a) Is the function an even function? yes no (b) Does the function have a period of P=2 π ? no yes

Choose the graph of y=sec x. Answer (a) and (b).
(a) Is the function an even function?
yes
no
(b) Does the function have a period of P=2 π ?
no
yes
Transcript text: Choose the graph of $y=\sec x$. Answer (a) and (b). (a) Is the function an even function? yes no (b) Does the function have a period of $P=2 \pi$ ? no yes
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Solution

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Solution Steps

Step 1: Identifying the correct graph of y = sec x

The secant function, sec(x), is the reciprocal of the cosine function, cos(x). It has vertical asymptotes where cos(x) = 0, which are at odd multiples of π/2. The second graph is the correct graph of y = sec x.

Step 2: Determining if y = sec x is an even function

An even function satisfies f(-x) = f(x) for all x in the domain. Since sec(x) = 1/cos(x) and cos(-x) = cos(x), it follows that sec(-x) = 1/cos(-x) = 1/cos(x) = sec(x). Thus, the secant function is an even function.

Step 3: Determining the period of y = sec x

The period of a function is the smallest positive value P such that f(x + P) = f(x) for all x. The cosine function has a period of 2π, meaning cos(x + 2π) = cos(x) for all x. Since sec(x) = 1/cos(x), it follows that sec(x + 2π) = 1/cos(x + 2π) = 1/cos(x) = sec(x). So, the secant function has a period of 2π.

Final Answer:

The correct graph is the second one. (a) yes, (b) yes

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