Questions: Point P is located at (-4,-7). P is reflected across the x-axis to create P'. In which quadrant is P' located?
Quadrant I
Quadrant II
Quadrant III
Quadrant IV
Transcript text: Point $P$ is located at $(-4,-7)$. $P$ is reflected across the $x$-axis to create $P^{\prime}$. In which quadrant is $P^{\prime}$ located?
Quadrant I
Quadrant II
Quadrant III
Quadrant IV
Solution
Solution Steps
Step 1: Understand the reflection rule
Reflecting a point across the \( x \)-axis changes the sign of the \( y \)-coordinate while keeping the \( x \)-coordinate the same. Mathematically, if a point \( P(x, y) \) is reflected across the \( x \)-axis, the new point \( P' \) will have coordinates \( (x, -y) \).
Step 2: Apply the reflection rule to point \( P \)
Given the original point \( P(-4, -7) \), reflecting it across the \( x \)-axis changes the \( y \)-coordinate from \(-7\) to \(7\). Thus, the coordinates of \( P' \) are:
\[
P'(-4, 7)
\]
Step 3: Determine the quadrant of \( P' \)
The point \( P'(-4, 7) \) has a negative \( x \)-coordinate and a positive \( y \)-coordinate. According to the quadrant definitions:
Quadrant I: \( x > 0 \), \( y > 0 \)
Quadrant II: \( x < 0 \), \( y > 0 \)
Quadrant III: \( x < 0 \), \( y < 0 \)
Quadrant IV: \( x > 0 \), \( y < 0 \)
Since \( P'(-4, 7) \) has \( x < 0 \) and \( y > 0 \), it lies in Quadrant II.