Questions: Point P is located at (-4,-7). P is reflected across the x-axis to create P'. In which quadrant is P' located? Quadrant I Quadrant II Quadrant III Quadrant IV

Point P is located at (-4,-7). P is reflected across the x-axis to create P'. In which quadrant is P' located?
Quadrant I
Quadrant II
Quadrant III
Quadrant IV
Transcript text: Point $P$ is located at $(-4,-7)$. $P$ is reflected across the $x$-axis to create $P^{\prime}$. In which quadrant is $P^{\prime}$ located? Quadrant I Quadrant II Quadrant III Quadrant IV
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Solution

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Solution Steps

Step 1: Understand the reflection rule

Reflecting a point across the \( x \)-axis changes the sign of the \( y \)-coordinate while keeping the \( x \)-coordinate the same. Mathematically, if a point \( P(x, y) \) is reflected across the \( x \)-axis, the new point \( P' \) will have coordinates \( (x, -y) \).

Step 2: Apply the reflection rule to point \( P \)

Given the original point \( P(-4, -7) \), reflecting it across the \( x \)-axis changes the \( y \)-coordinate from \(-7\) to \(7\). Thus, the coordinates of \( P' \) are: \[ P'(-4, 7) \]

Step 3: Determine the quadrant of \( P' \)

The point \( P'(-4, 7) \) has a negative \( x \)-coordinate and a positive \( y \)-coordinate. According to the quadrant definitions:

  • Quadrant I: \( x > 0 \), \( y > 0 \)
  • Quadrant II: \( x < 0 \), \( y > 0 \)
  • Quadrant III: \( x < 0 \), \( y < 0 \)
  • Quadrant IV: \( x > 0 \), \( y < 0 \)

Since \( P'(-4, 7) \) has \( x < 0 \) and \( y > 0 \), it lies in Quadrant II.

Final Answer

\[ \boxed{\text{Quadrant II}} \]

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