Questions: A manufacturer of tools, selling rechargeable drills to a chain of home improvement stores, charges 4 more per drill than its manufacturing cost, m . The chain then sells each drill for 150% of the price that it paid the manufacturer. Find a function P(m) for the price at the home improvement stores. The function for the price at the home improvement stores is given by P(m)=

A manufacturer of tools, selling rechargeable drills to a chain of home improvement stores, charges 4 more per drill than its manufacturing cost, m . The chain then sells each drill for 150% of the price that it paid the manufacturer. Find a function P(m) for the price at the home improvement stores. The function for the price at the home improvement stores is given by P(m)=
Transcript text: A manufacturer of tools, selling rechargeable drills to a chain of home improvement stores, charges $\$ 4$ more per drill than its manufacturing cost, m . The chain then sells each drill for $150 \%$ of the price that it paid the manufacturer. Find a function $\mathrm{P}(\mathrm{m})$ for the price at the home improvement stores. The function for the price at the home improvement stores is given by $P(m)=$ $\square$
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Solution

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Solution Steps

Step 1: Calculate the manufacturer's selling price

To find the manufacturer's selling price, we add the additional charge \(x\) to the manufacturing cost \(m\). \[\text{Manufacturer's selling price} = m + x = 0 + 4 = 4\]

Step 2: Calculate the final selling price at the stores

To find the final selling price at the stores, we multiply the manufacturer's selling price by \(\frac{y}{100}\) to convert the percentage into a decimal. \[\text{Final selling price} = (m + x) \times \frac{y}{100} = (0 + 4) \times \frac{150}{100} = 6\]

Final Answer:

The final selling price at the stores, rounded to 0 decimal places, is \(\$6\).

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