To solve the given probability questions, we need to follow these steps:
The total number of balls in the jar is calculated as follows: Total Balls=Red Balls+White Balls+Yellow Balls=6+4+7=17 \text{Total Balls} = \text{Red Balls} + \text{White Balls} + \text{Yellow Balls} = 6 + 4 + 7 = 17 Total Balls=Red Balls+White Balls+Yellow Balls=6+4+7=17
The probability of drawing a red ball P(A) P(A) P(A) is given by the ratio of the number of red balls to the total number of balls: P(A red ball is drawn)=Red BallsTotal Balls=617≈0.3529 P(A \text{ red ball is drawn}) = \frac{\text{Red Balls}}{\text{Total Balls}} = \frac{6}{17} \approx 0.3529 P(A red ball is drawn)=Total BallsRed Balls=176≈0.3529
The probability of drawing a ball that is not red P(B) P(B) P(B) can be calculated as: P(The ball drawn is NOT red)=1−P(A)=1−617=1117≈0.6471 P(\text{The ball drawn is NOT red}) = 1 - P(A) = 1 - \frac{6}{17} = \frac{11}{17} \approx 0.6471 P(The ball drawn is NOT red)=1−P(A)=1−176=1711≈0.6471
Since there are no green balls in the jar, the probability of drawing a green ball P(C) P(C) P(C) is: P(A green ball is drawn)=Green BallsTotal Balls=017=0.0 P(A \text{ green ball is drawn}) = \frac{\text{Green Balls}}{\text{Total Balls}} = \frac{0}{17} = 0.0 P(A green ball is drawn)=Total BallsGreen Balls=170=0.0
P(A red ball is drawn)=617,P(The ball drawn is NOT red)=1117,P(A green ball is drawn)=0.0 \boxed{P(A \text{ red ball is drawn}) = \frac{6}{17}, \quad P(\text{The ball drawn is NOT red}) = \frac{11}{17}, \quad P(A \text{ green ball is drawn}) = 0.0} P(A red ball is drawn)=176,P(The ball drawn is NOT red)=1711,P(A green ball is drawn)=0.0
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