Questions: How many grams of gold (Au) are there in 93.37 moles of Au? Be sure your answer has the correct number of significant digits. g Au × 10^1

How many grams of gold (Au) are there in 93.37 moles of Au? Be sure your answer has the correct number of significant digits. g Au × 10^1
Transcript text: How many grams of gold (Au)are there in 93.37 moles of Au ? Be sure your answer has the correct number of significant digit $\square$ g Au $\square$ $\times 10^{1}$
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Solution

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Solution Steps

Step 1: Determine the Molar Mass of Gold

The molar mass of gold (Au) is approximately 196.97 grams per mole. This value is used to convert moles of gold to grams.

Step 2: Calculate the Mass of Gold

To find the mass of gold in grams, multiply the number of moles by the molar mass:

\[ \text{Mass of Au} = \text{Number of moles} \times \text{Molar mass of Au} \]

Substituting the given values:

\[ \text{Mass of Au} = 93.37 \, \text{moles} \times 196.97 \, \text{g/mole} \]

Step 3: Perform the Calculation

Calculate the product:

\[ \text{Mass of Au} = 18400.6489 \, \text{g} \]

Step 4: Round to the Correct Number of Significant Figures

The number of significant figures in the given number of moles (93.37) is four. Therefore, the final answer should also be rounded to four significant figures:

\[ \text{Mass of Au} = 18400.65 \, \text{g} \]

Final Answer

\[ \boxed{18400.65 \, \text{g Au}} \]

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