Questions: 30 OF 30 QUESTIONS REMAINING A p-type semiconductor joined to an n-type semiconductor ... Pick those that apply. (A) Makes a diode B In a circuit allows electrons to flow from the n-type to the p-type material (C) Is a component of a transistor D In a circuit allows positive current (e.g. holes) to flow from the p-type to the n-type material.

30 OF 30 QUESTIONS REMAINING A p-type semiconductor joined to an n-type semiconductor ... Pick those that apply. (A) Makes a diode B In a circuit allows electrons to flow from the n-type to the p-type material (C) Is a component of a transistor D In a circuit allows positive current (e.g. holes) to flow from the p-type to the n-type material.
Transcript text: 30 OF 30 QUESTIONS REMAINING A p-type semiconductor joined to an n-type semiconductor ... Pick those that apply. (A) Makes a diode B In a circuit allows electrons to flow from the n-type to the p-type material (C) Is a component of a transistor D In a circuit allows positive current (e.g. holes) to flow from the p-type to the n-type material.
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Solution

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Solution Steps

Step 1: Understanding the p-n Junction

A p-type semiconductor has an abundance of holes (positive charge carriers), while an n-type semiconductor has an abundance of electrons (negative charge carriers). When these two types of semiconductors are joined, they form a p-n junction, which is the basic building block of many semiconductor devices.

Step 2: Analyzing the Options
  • Option A: A p-n junction indeed forms a diode, which is a device that allows current to flow in one direction. Therefore, this option is correct.
  • Option B: In a circuit, electrons flow from the n-type to the p-type material when the diode is forward-biased. This is a correct statement.
  • Option C: A p-n junction is a fundamental component of a transistor, which typically consists of multiple p-n junctions. This option is correct.
  • Option D: In a circuit, positive current (holes) flows from the p-type to the n-type material when the diode is forward-biased. This is also a correct statement.

Final Answer

\[ \boxed{\text{A, B, C, D}} \]

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