Questions: Warren runs races to support local charities. In April, he ran a 5-kilometer race in 30 minutes to support his local hospital. In October, he will run a 10 -kilometer race to support the animal shelter. If he runs at the same rate, how many minutes will it take Warren to run the race in October?

Determine the time it will take Warren to run the 10-kilometer race in October if he runs at the same rate as in April.

Find Warren's running rate in April.

Warren ran 5 kilometers in 30 minutes. His rate is calculated as:
$$\text{Rate} = \frac{\text{Distance}}{\text{Time}} = \frac{5 \, \text{km}}{30 \, \text{min}} = \frac{1}{6} \, \text{km/min}.$$

Calculate the time required to run 10 kilometers at the same rate.

Using the rate $\frac{1}{6} \, \text{km/min}$, the time $t$ to run 10 kilometers is:
$$t = \frac{\text{Distance}}{\text{Rate}} = \frac{10 \, \text{km}}{\frac{1}{6} \, \text{km/min}} = 60 \, \text{min}.$$

The time it will take Warren to run the 10-kilometer race in October is $\boxed{60 \, \text{min}}$.

The time it will take Warren to run the 10-kilometer race in October is $\boxed{60 \, \text{min}}$.