Questions: Find the probability of z occurring in the indicated region of the standard normal distribution. P(0<z<2.03)=□ (Round to four decimal places as needed.)

Find the probability of z occurring in the indicated region of the standard normal distribution. P(0<z<2.03)=□ (Round to four decimal places as needed.)
Transcript text: Find the probability of $z$ occurring in the indicated region of the standard normal distribution. \[ P(0
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Solution

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Solution Steps

Step 1: Find the area corresponding to z=2.03

From the standard normal distribution table (page 2), the area to the left of z = 2.03 is 0.9788.

Step 2: Find the area to the left of z=0

The standard normal distribution is symmetric about z=0. The area to the left of z=0 is 0.5.

Step 3: Calculate the area between z=0 and z=2.03

The area between z=0 and z=2.03 is the difference between the area to the left of z=2.03 and the area to the left of z=0. P(0 < z < 2.03) = P(z < 2.03) - P(z < 0) P(0 < z < 2.03) = 0.9788 - 0.5 P(0 < z < 2.03) = 0.4788

Final Answer

0.4788

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