Questions: Write an augmented matrix and use elementary row operations in order to solve the following system of equations. Your final matrix should be in reduced row echelon form. In order to get credit you will have to have a correct final answer as accurate steps in each row operation. (x - 5y = 7) (5x + 8y = -4) Write the augmented matrix: [ ][ ][ ] [ ][ ][ ]

Write an augmented matrix and use elementary row operations in order to solve the following system of equations. Your final matrix should be in reduced row echelon form. In order to get credit you will have to have a correct final answer as accurate steps in each row operation.

(x - 5y = 7)
(5x + 8y = -4)

Write the augmented matrix:

[   ][   ][   ]
[   ][   ][   ]
Transcript text: Solve 2 by 2 System of Equations with Matrices (Guided) Score: 0/1 Penalty: 1.0% Question Write an augmented matrix and use elementary row operations in order to solve the following system of equations. Your final matrix should be in reduced row echelon form. In order to get credit you will have to have a correct final answer as accurate steps in each row operation. $x - 5y = 7$ $5x + 8y = -4$ Write the augmented matrix: [ ][ ][ ] [ ][ ][ ] enter matrix Answer: Attempt 1 out of 6 You must answer all questions above in order to submit.
failed

Solution

failed
failed

Solution Steps

To solve the given system of equations using matrices, we first write the system as an augmented matrix. Then, we perform elementary row operations to transform the matrix into reduced row echelon form (RREF). This will allow us to read off the solutions for \(x\) and \(y\).

Step 1: Write the Augmented Matrix

The given system of equations is: \[ \begin{align_} x - 5y &= 7 \\ 5x + 8y &= -4 \end{align_} \] We can represent this system as an augmented matrix: \[ A = \begin{bmatrix} 1 & -5 & 7 \\ 5 & 8 & -4 \end{bmatrix} \]

Step 2: Perform Row Operations

We will perform elementary row operations to convert the matrix into reduced row echelon form (RREF).

  1. Eliminate the first element of the second row: \[ R_2 = R_2 - 5R_1 \implies R_2 = \begin{bmatrix} 0 & 1 & -1.18181818 \end{bmatrix} \]

  2. Normalize the second row: \[ R_2 = \frac{R_2}{1} \implies R_2 = \begin{bmatrix} 0 & 1 & -1.18181818 \end{bmatrix} \]

  3. Eliminate the second element of the first row: \[ R_1 = R_1 + 5R_2 \implies R_1 = \begin{bmatrix} 1 & 0 & 1.09090909 \end{bmatrix} \]

The matrix is now in RREF: \[ \begin{bmatrix} 1 & 0 & 1.09090909 \\ 0 & 1 & -1.18181818 \end{bmatrix} \]

Step 3: Extract Solutions

From the RREF, we can read the solutions: \[ x = 1.0909 \quad \text{(rounded to four significant digits)} \] \[ y = -1.1818 \quad \text{(rounded to four significant digits)} \]

Final Answer

The solutions to the system of equations are: \[ \boxed{x = 1.0909} \] \[ \boxed{y = -1.1818} \]

Was this solution helpful?
failed
Unhelpful
failed
Helpful