Questions: QUESTION 26 A 9 kg block experiences a net force in the opposite direction of its velocity for 1 s. Its velocity decreases by 12 m / s. What is the magnitude of the net force? Calculate answer to one decimal.

QUESTION 26

A 9 kg block experiences a net force in the opposite direction of its velocity for 1 s. Its velocity decreases by 12 m / s. What is the magnitude of the net force?

Calculate answer to one decimal.

Transcript text: QUESTION 26 A 9 kg block experiences a net force in the opposite direction of its velocity for 1 s . Its velocity decreases by $12 \mathrm{~m} / \mathrm{s}$. What is the magnitude of the net force? Calculate answer to one decimal. $\square$

Solution

Solution Steps

Step 1: Identify the given values

We are given:

Mass of the block, $ m = 9 \, \text{kg} $
Time duration, $ t = 1 \, \text{s} $
Change in velocity, $ \Delta v = 12 \, \text{m/s} $

Step 2: Use Newton's Second Law

Newton's Second Law states that the net force $ F $ acting on an object is equal to the mass $ m $ of the object multiplied by its acceleration $ a $: \[ F = m \cdot a \]

Step 3: Calculate the acceleration

Acceleration $ a $ can be calculated using the change in velocity $ \Delta v $ over the time $ t $: \[ a = \frac{\Delta v}{t} = \frac{12 \, \text{m/s}}{1 \, \text{s}} = 12 \, \text{m/s}^2 \]

Step 4: Calculate the net force

Substitute the values of $ m $ and $ a $ into the equation $ F = m \cdot a $: \[ F = 9 \, \text{kg} \cdot 12 \, \text{m/s}^2 = 108 \, \text{N} \]