Questions: f(x)=x^3+7 x^2-16 x-112 Determine the behavior of the function at each zero.

f(x)=x^3+7 x^2-16 x-112

Determine the behavior of the function at each zero.
Transcript text: \[ f(x)=x^{3}+7 x^{2}-16 x-112 \] Determine the behavior of the function at each zero.
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Solution

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Solution Steps

To determine the behavior of the function at each zero, we first need to find the roots of the polynomial \( f(x) = x^3 + 7x^2 - 16x - 112 \). Once the roots are found, we can analyze the behavior of the function around each root by examining the sign changes in the intervals around the roots. This involves checking the derivative to understand the nature of each zero (whether it is a local minimum, maximum, or a point of inflection).

Step 1: Finding the Roots

The roots of the polynomial \( f(x) = x^3 + 7x^2 - 16x - 112 \) are found to be: \[ x = -7, \quad x = -4, \quad x = 4 \]

Step 2: Calculating the Derivative

The derivative of the function is given by: \[ f'(x) = 3x^2 + 14x - 16 \]

Step 3: Analyzing the Behavior at Each Root

We evaluate the derivative at each root to determine the behavior of the function:

  1. For \( x = -7 \): \[ f'(-7) = 3(-7)^2 + 14(-7) - 16 = 147 - 98 - 16 = 33 > 0 \quad \text{(local minimum)} \]

  2. For \( x = -4 \): \[ f'(-4) = 3(-4)^2 + 14(-4) - 16 = 48 - 56 - 16 = -24 < 0 \quad \text{(local maximum)} \]

  3. For \( x = 4 \): \[ f'(4) = 3(4)^2 + 14(4) - 16 = 48 + 56 - 16 = 88 > 0 \quad \text{(local minimum)} \]

Final Answer

The behavior of the function at each zero is:

  • At \( x = -7 \): local minimum
  • At \( x = -4 \): local maximum
  • At \( x = 4 \): local minimum

Thus, the final answer is: \[ \boxed{ \begin{aligned} &\text{At } x = -7: \text{ local minimum} \\ &\text{At } x = -4: \text{ local maximum} \\ &\text{At } x = 4: \text{ local minimum} \end{aligned} } \]

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