Questions: 2x^-3y^-3 / (2xy^3 cdot (2x^-3)^4)

2x^-3y^-3 / (2xy^3 cdot (2x^-3)^4)
Transcript text: $\frac{2 x^{-3} y^{-3}}{2 x y^{3} \cdot\left(2 x^{-3}\right)^{4}}$
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Solution

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Solution Steps

To simplify the given expression, we need to follow these steps:

  1. Simplify the numerator and the denominator separately.
  2. Combine the simplified forms.
  3. Apply the laws of exponents to further simplify the expression.
Step 1: Simplify the Numerator

The numerator of the given expression is: \[ 2 x^{-3} y^{-3} \]

Step 2: Simplify the Denominator

The denominator of the given expression is: \[ 2 x y^{3} \cdot (2 x^{-3})^{4} \]

First, simplify \((2 x^{-3})^{4}\): \[ (2 x^{-3})^{4} = 2^{4} \cdot (x^{-3})^{4} = 16 x^{-12} \]

So, the denominator becomes: \[ 2 x y^{3} \cdot 16 x^{-12} = 32 x^{-11} y^{3} \]

Step 3: Combine and Simplify the Expression

Now, combine the simplified numerator and denominator: \[ \frac{2 x^{-3} y^{-3}}{32 x^{-11} y^{3}} \]

Simplify the fraction: \[ \frac{2}{32} \cdot \frac{x^{-3}}{x^{-11}} \cdot \frac{y^{-3}}{y^{3}} = \frac{1}{16} \cdot x^{8} \cdot y^{-6} \]

Thus, the simplified expression is: \[ \frac{x^{8}}{16 y^{6}} \]

Final Answer

\[ \boxed{\frac{x^{8}}{16 y^{6}}} \]

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