Questions: Los Angeles workers have an average commute of 29 minutes. Suppose the LA commute time is normally distributed with a standard deviation of 15 minutes. Let X represent the commute time for a randomly selected LA worker. Round all answers to 4 decimal places where possible. a. What is the distribution of X ? X-NC (29, 15) b. Find the probability that a randomly selected LA worker has a commute that is longer than 37 minutes. c. Find the 85th percentile for the commute time of LA workers. minutes

Los Angeles workers have an average commute of 29 minutes. Suppose the LA commute time is normally distributed with a standard deviation of 15 minutes. Let X represent the commute time for a randomly selected LA worker. Round all answers to 4 decimal places where possible.

a. What is the distribution of X ? X-NC (29, 15)
b. Find the probability that a randomly selected LA worker has a commute that is longer than 37 minutes.

c. Find the 85th percentile for the commute time of LA workers.  minutes
Transcript text: Los Angeles workers have an average commute of 29 minutes. Suppose the LA commute time is normally distributed with a standard deviation of 15 minutes. Let $X$ represent the commute time for a randomly selected LA worker. Round all answers to 4 decimal places where possible. a. What is the distribution of X ? $\mathrm{X}-\mathrm{NC}$ $\square$ , $\square$ ) b. Find the probability that a randomly selected LA worker has a commute that is longer than 37 minutes. $\square$ c. Find the 85 th percentile for the commute time of LA workers. $\square$ minutes Hint: Helpful videos: - Find a Probability [+]
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Solution

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Solution Steps

Step 1: Distribution of \( X \)

The random variable \( X \), representing the commute time for a randomly selected LA worker, follows a normal distribution. Specifically, we have:

\[ X \sim N(29, 15) \]

Step 2: Probability of Commute Time Longer than 37 Minutes

To find the probability that a randomly selected LA worker has a commute time longer than 37 minutes, we calculate:

\[ P(X > 37) = 1 - P(X \leq 37) \]

First, we find the Z-score for \( X = 37 \):

\[ Z = \frac{X - \mu}{\sigma} = \frac{37 - 29}{15} = \frac{8}{15} \approx 0.5333 \]

Using the cumulative distribution function \( \Phi \):

\[ P(X \leq 37) = \Phi(0.5333) \approx 0.2969 \]

Thus, the probability is:

\[ P(X > 37) = 1 - 0.2969 = 0.7031 \]

Step 3: 85th Percentile of Commute Time

To find the 85th percentile, we need to determine the value \( x \) such that:

\[ P(X \leq x) = 0.85 \]

Using the inverse of the cumulative distribution function, we find:

\[ x = \Phi^{-1}(0.85) \approx 44.5465 \]

Final Answer

  • a. The distribution of \( X \) is \( N(29, 15) \).
  • b. The probability that a randomly selected LA worker has a commute longer than 37 minutes is \( 0.7031 \).
  • c. The 85th percentile for the commute time of LA workers is \( 44.5465 \) minutes.

\[ \boxed{ \begin{align_} \text{a.} & \quad N(29, 15) \\ \text{b.} & \quad 0.7031 \\ \text{c.} & \quad 44.5465 \text{ minutes} \end{align_} } \]

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