Questions: Cantaloupe, radii 4 and 6, 30 degree slice. 4 ≤ ρ ≤ 6 0 ≤ φ ≤ π 0 ≤ θ ≤ π/6 √(16-r^2) ≤ z ≤ √(36-r^2) 4 ≤ r ≤ 6 0 ≤ θ ≤ π/6 4 ≤ z ≤ 6 0 ≤ φ ≤ π/2 0 ≤ θ ≤ π/6

Cantaloupe, radii 4 and 6, 30 degree slice.
4 ≤ ρ ≤ 6
0 ≤ φ ≤ π
0 ≤ θ ≤ π/6
√(16-r^2) ≤ z ≤ √(36-r^2)
4 ≤ r ≤ 6
0 ≤ θ ≤ π/6
4 ≤ z ≤ 6
0 ≤ φ ≤ π/2
0 ≤ θ ≤ π/6
Transcript text: Cantaloupe, radii 4 and 6, 30 degree slice. $4 \leq \rho \leq 6$ $0 \leq \phi \leq \pi$ $0 \leq \theta \leq \frac{\pi}{6}$ $\sqrt{16-r^{2}} \leq z \leq \sqrt{36-r^{2}}$ $4 \leq r \leq 6$ $0 \leq \theta \leq \frac{\pi}{6}$ $4 \leq z \leq 6$ $0 \leq \phi \leq \frac{\pi}{2}$ $0 \leq \theta \leq \frac{\pi}{6}$
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Solution

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Solution Steps

Step 1: Analyze the problem

We are asked to determine the bounds of a cantaloupe slice in spherical coordinates. The cantaloupe has inner radius 4 and outer radius 6. The slice covers 30 degrees, or π/6 radians.

Step 2: Determine ρ

The radial distance, ρ, goes from the inner radius to the outer radius. Thus, 4 ≤ ρ ≤ 6.

Step 3: Determine Φ

The angle Φ sweeps down from the z-axis. The image shows that we have a full rotation, meaning Φ goes from 0 to π. So, 0 ≤ Φ ≤ π.

Step 4: Determine θ

The angle θ is given as a 30 degree slice (π/6 radians). From the bottom images, we can see that θ sweeps from the y-axis to the slice. This means the angle starts at zero and sweeps to π/6. Thus, 0 ≤ θ ≤ π/6.

Final Answer:

4 ≤ ρ ≤ 6 0 ≤ Φ ≤ π 0 ≤ θ ≤ π/6

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