Questions: Let f(x)=(4.5)^x Find x such that f(x)=528.38 Round your final answer to two decimal places?

Let f(x)=(4.5)^x  Find x such that f(x)=528.38

Round your final answer to two decimal places?
Transcript text: Let $f(x)=(4.5)^{x} \quad$ Find $x$ such that $f(x)=528.38$ Round your final answer to two decimal places? $\square$
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Solution

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Solution Steps

To find x x such that f(x)=528.38 f(x) = 528.38 for the function f(x)=(4.5)x f(x) = (4.5)^x , we need to solve the equation (4.5)x=528.38 (4.5)^x = 528.38 . This can be done by taking the logarithm of both sides and then solving for x x .

Step 1: Set Up the Equation

We start with the function defined as f(x)=(4.5)x f(x) = (4.5)^x and set it equal to the given value:

(4.5)x=528.38 (4.5)^x = 528.38

Step 2: Apply Logarithms

To solve for x x , we take the logarithm of both sides:

log((4.5)x)=log(528.38) \log((4.5)^x) = \log(528.38)

Using the property of logarithms, we can simplify the left side:

xlog(4.5)=log(528.38) x \cdot \log(4.5) = \log(528.38)

Step 3: Solve for x x

Now, we isolate x x :

x=log(528.38)log(4.5) x = \frac{\log(528.38)}{\log(4.5)}

Calculating the values gives us:

x4.1685 x \approx 4.1685

Rounding this to two decimal places, we find:

x4.17 x \approx 4.17

Final Answer

x=4.17\boxed{x = 4.17}

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