To multiply and simplify the given polynomials \((9z + 4)(9z - 4)\), we can use the difference of squares formula, which states that \((a + b)(a - b) = a^2 - b^2\). Here, \(a = 9z\) and \(b = 4\).
Step 1: Apply the Difference of Squares Formula
To multiply the polynomials \((9z + 4)(9z - 4)\), we recognize that this expression fits the difference of squares pattern, which is given by:
\[
(a + b)(a - b) = a^2 - b^2
\]
Here, we set \(a = 9z\) and \(b = 4\).
Step 2: Calculate \(a^2\) and \(b^2\)
Now, we compute \(a^2\) and \(b^2\):
\[
a^2 = (9z)^2 = 81z^2
\]
\[
b^2 = 4^2 = 16
\]
Step 3: Substitute into the Formula
Substituting these values back into the difference of squares formula, we have:
\[
(9z + 4)(9z - 4) = a^2 - b^2 = 81z^2 - 16
\]
Final Answer
Thus, the simplified result of the multiplication is:
\[
\boxed{81z^2 - 16}
\]