Questions: Which represents the oxidation number of each of the elements in BaNaPO4? +2; +4; +5; +2 +2; +1; +5; -2 +1; +2; +5; -2 +2; +1; +4; -2 +1; +1; -5; -2

Which represents the oxidation number of each of the elements in BaNaPO4?
+2; +4; +5; +2
+2; +1; +5; -2
+1; +2; +5; -2
+2; +1; +4; -2
+1; +1; -5; -2

Transcript text: 18. Which represents the oxidation number of each of the elements in $\mathrm{BaNaPO}_{4}$ ? $+2 ;+4 ;+5 ;+2$ $+2 ;+1 ;+5 ;-2$ $+1 ;+2 ;+5 ;-2$ $+2 ;+1 ;+4 ;-2$ $+1 ;+1 ;-5 ;-2$

Solution

Solution Steps

Step 1: Identify the Elements and Their Common Oxidation States

In the compound $\mathrm{BaNaPO}_{4}$ , the elements present are Barium (Ba), Sodium (Na), Phosphorus (P), and Oxygen (O). We need to determine the oxidation number of each element.

Step 2: Assign Known Oxidation Numbers

Barium (Ba) typically has an oxidation number of $+2$ .
Sodium (Na) typically has an oxidation number of $+1$ .
Oxygen (O) typically has an oxidation number of $-2$ .

Step 3: Determine the Oxidation Number of Phosphorus (P)

The compound $\mathrm{BaNaPO}_{4}$ is neutral, so the sum of the oxidation numbers of all the atoms must equal zero.

Let the oxidation number of Phosphorus (P) be $x$ .

The total oxidation number can be calculated as: $(+2) + (+1) + x + 4(-2) = 0$

Step 4: Solve for the Oxidation Number of Phosphorus (P)

$2 + 1 + x - 8 = 0$ $3 + x - 8 = 0$ $x - 5 = 0$ $x = +5$

Final Answer

The oxidation numbers of the elements in $\mathrm{BaNaPO}_{4}$ are:

Barium (Ba): $+2$
Sodium (Na): $+1$
Phosphorus (P): $+5$
Oxygen (O): $-2$

Thus, the correct answer is: $\boxed{+2 ;+1 ;+5 ;-2}$

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