Questions: Both water and sulfur dioxide are products from the reaction of Sulfuric acid (H2SO4) with Copper metal as shown 2 H2SO4 + Cu -> SO2 + 2 H2O + CuSO4 How many grams of H2O will be produced at the same time that 10 grams of SO2 is produced

Solution Steps

The molar mass of sulfur dioxide (SO\(_2\)) is calculated as follows:

• Sulfur (S): 32.07 g/mol
• Oxygen (O): 16.00 g/mol

\[ \text{Molar mass of SO}_2 = 32.07 + 2 \times 16.00 = 64.07 \, \text{g/mol} \]

Given 10 grams of SO\(_2\), we convert this to moles using its molar mass:

\[ 10 \, \text{g SO}_2 \times \frac{1 \, \text{mol SO}_2}{64.07 \, \text{g SO}_2} = 0.1561 \, \text{mol SO}_2 \]

From the balanced chemical equation, 1 mole of SO\(_2\) produces 2 moles of H\(_2\)O. Therefore, the moles of H\(_2\)O produced are:

\[ 0.1561 \, \text{mol SO}_2 \times \frac{2 \, \text{mol H}_2\text{O}}{1 \, \text{mol SO}_2} = 0.3122 \, \text{mol H}_2\text{O} \]

The molar mass of water (H\(_2\)O) is 18.015 g/mol. Convert moles of H\(_2\)O to grams:

\[ 0.3122 \, \text{mol H}_2\text{O} \times 18.015 \, \text{g/mol} = 5.624 \, \text{g H}_2\text{O} \]

Final Answer