Questions: Find the center-radius form of the equation of the circle described. Then graph the circle. center (sqrt(5), sqrt(6)), radius sqrt(2) Type the center-radius form of the equation of the circle described.

Find the center-radius form of the equation of the circle described. Then graph the circle.
center (sqrt(5), sqrt(6)), radius sqrt(2)

Type the center-radius form of the equation of the circle described.
Transcript text: Find the center-radius form of the equation of the circle described. Then graph the circle. center $(\sqrt{5}, \sqrt{6})$, radius $\sqrt{2}$ Type the center-radius form of the equation of the circle described. $\square$ (Simplify your answer.)
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Solution

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Solution Steps

Step 1: Identify the center and radius of the circle

The center of the circle is given as \((\sqrt{5}, \sqrt{6})\) and the radius is \(\sqrt{2}\).

Step 2: Write the center-radius form of the circle's equation

The center-radius form of a circle's equation is given by: \[ (x - h)^2 + (y - k)^2 = r^2 \] where \((h, k)\) is the center and \(r\) is the radius. Substituting the given values: \[ (x - \sqrt{5})^2 + (y - \sqrt{6})^2 = (\sqrt{2})^2 \]

Step 3: Simplify the equation

Simplify the equation by squaring the radius: \[ (x - \sqrt{5})^2 + (y - \sqrt{6})^2 = 2 \]

Final Answer

The center-radius form of the equation of the circle is: \[ (x - \sqrt{5})^2 + (y - \sqrt{6})^2 = 2 \]

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