Questions: Blood pressure: A blood pressure measurement consists of two numbers: the systolic pressure, which is the maximum pressure taken when the heart is contracting, and the diastolic pressure, which is the minimum pressure taken at the beginning of the heartbeat. Blood pressures were measured, in millimeters of mercury (mmHg), for a sample of 10 adults. The following table presents the results. Systolic Diastolic - 115 83 - 113 77 - 123 77 - 119 69 - 118 88 - 130 76 - 116 70 - 133 91 - 112 75 - 107 71 Based on results published in the Journal of Human Hypertension Part 1 of 4 Compute the least-squares regression line for predicting the diastolic pressure (y) from the systolic pressure (x). Round the slope and (y)-intercept to at least four decimal places. Regression line equation: ŷ = .

Blood pressure: A blood pressure measurement consists of two numbers: the systolic pressure, which is the maximum pressure taken when the heart is contracting, and the diastolic pressure, which is the minimum pressure taken at the beginning of the heartbeat. Blood pressures were measured, in millimeters of mercury (mmHg), for a sample of 10 adults. The following table presents the results.

Systolic  Diastolic
- 115  83
- 113  77
- 123  77
- 119  69
- 118  88
- 130  76
- 116  70
- 133  91
- 112  75
- 107  71

Based on results published in the Journal of Human Hypertension

Part 1 of 4 Compute the least-squares regression line for predicting the diastolic pressure (y) from the systolic pressure (x). Round the slope and (y)-intercept to at least four decimal places. Regression line equation: ŷ = .
Transcript text: Blood pressure: A blood pressure measurement consists of two numbers: the systolic pressure, which is the maximum pressure taken when the heart is contracting, and the diastolic pressure, which is the minimum pressure taken at the beginning of the heartbeat. Blood pressures were measured, in millimeters of mercury ( mmHg ), for a sample of 10 adults. The following table presents the results. \begin{tabular}{cc} \hline Systolic & Diastolic \\ \hline 115 & 83 \\ 113 & 77 \\ 123 & 77 \\ 119 & 69 \\ 118 & 88 \\ 130 & 76 \\ 116 & 70 \\ 133 & 91 \\ 112 & 75 \\ 107 & 71 \\ \hline \end{tabular} Based on results published in the Journal of Human Hypertension Send data to Exced Parti $0 / 4$ Part 1 of 4 Compute the least-squares regression line for predicting the diastolic pressure $(y)$ from the systolic pressure $(x)$. Round the slope and $(y)$-intercept to at least four decimal places. Regression line equation: $\hat{y}=$ $\square$ .
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Solution

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Solution Steps

Step 1: Calculate the Means

The means of the systolic and diastolic pressures are calculated as follows:

\[ \bar{x} = \frac{1}{n} \sum_{i=1}^{n} x_i = \frac{1}{10} (115 + 113 + 123 + 119 + 118 + 130 + 116 + 133 + 112 + 107) = 118.6 \]

\[ \bar{y} = \frac{1}{n} \sum_{i=1}^{n} y_i = \frac{1}{10} (83 + 77 + 77 + 69 + 88 + 76 + 70 + 91 + 75 + 71) = 77.7 \]

Step 2: Calculate the Correlation Coefficient

The correlation coefficient \( r \) is computed as follows:

\[ r = 0.4788 \]

Step 3: Calculate the Numerator and Denominator for the Slope

The numerator for the slope \( \beta \) is given by:

\[ \text{Numerator for } \beta = \sum_{i=1}^{n} x_i y_i - n \bar{x} \bar{y} = 92412 - 10 \cdot 118.6 \cdot 77.7 = 259.8 \]

The denominator for the slope \( \beta \) is calculated as:

\[ \text{Denominator for } \beta = \sum_{i=1}^{n} x_i^2 - n \bar{x}^2 = 141246 - 10 \cdot (118.6)^2 = 586.4 \]

Step 4: Calculate the Slope and Intercept

The slope \( \beta \) is computed as:

\[ \beta = \frac{259.8}{586.4} = 0.443 \]

The intercept \( \alpha \) is calculated using:

\[ \alpha = \bar{y} - \beta \bar{x} = 77.7 - 0.443 \cdot 118.6 = 25.1552 \]

Step 5: Write the Regression Line Equation

The equation of the regression line is:

\[ \hat{y} = \alpha + \beta x = 25.1552 + 0.443x \]

Final Answer

The slope and intercept of the regression line are:

\[ \text{Slope (}\beta\text{): } 0.443 \] \[ \text{Intercept (}\alpha\text{): } 25.1552 \]

The regression line equation is:

\[ \hat{y} = 25.1552 + 0.443x \]

Thus, the final boxed answer is:

\[ \boxed{\hat{y} = 25.1552 + 0.443x} \]

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