Questions: Evaluating an exponential function with base e that models a real-world...
A species of fish was added to a lake. The population size P(t) of this species can be modeled by the following function, where t is the number of years from the time the species was added to the lake.
P(t) = 1200 / (1 + 2 e^(-0.3 t))
Find the initial population size of the species and the population size after 8 years. Round your answers to the nearest whole number as necessary.
Initial population size: fish
Population size after 8 years: fish
Transcript text: Evaluating an exponential function with base e that models a real-world...
A species of fish was added to a lake. The population size $P(t)$ of this species can be modeled by the following function, where $t$ is the number of years from the time the species was added to the lake.
\[
P(t)=\frac{1200}{1+2 e^{-0.3 t}}
\]
Find the initial population size of the species and the population size after 8 years.
Round your answers to the nearest whole number as necessary.
Initial population size:
fish
Population size after 8 years: $\square$ fish
Solution
Solution Steps
To find the initial population size, evaluate the function \( P(t) \) at \( t = 0 \). For the population size after 8 years, evaluate the function at \( t = 8 \). Use Python to compute these values and round the results to the nearest whole number.
Step 1: Initial Population Size
To find the initial population size, we evaluate the function \( P(t) \) at \( t = 0 \):
\[
P(0) = \frac{1200}{1 + 2 e^{-0.3 \cdot 0}} = \frac{1200}{1 + 2 \cdot 1} = \frac{1200}{3} = 400
\]
Thus, the initial population size is \( 400 \) fish.
Step 2: Population Size After 8 Years
Next, we evaluate the function \( P(t) \) at \( t = 8 \):
\[
P(8) = \frac{1200}{1 + 2 e^{-0.3 \cdot 8}} = \frac{1200}{1 + 2 e^{-2.4}}
\]
Calculating \( e^{-2.4} \) gives approximately \( 0.090717953 \):
\[
P(8) = \frac{1200}{1 + 2 \cdot 0.090717953} = \frac{1200}{1 + 0.181435906} = \frac{1200}{1.181435906} \approx 1016
\]
Thus, the population size after 8 years is \( 1016 \) fish.
Final Answer
The initial population size is \( 400 \) fish and the population size after 8 years is \( 1016 \) fish. Therefore, the answers are:
\[
\boxed{400 \text{ fish}}
\]
\[
\boxed{1016 \text{ fish}}
\]