Questions: Evaluating an exponential function with base e that models a real-world... A species of fish was added to a lake. The population size P(t) of this species can be modeled by the following function, where t is the number of years from the time the species was added to the lake. P(t) = 1200 / (1 + 2 e^(-0.3 t)) Find the initial population size of the species and the population size after 8 years. Round your answers to the nearest whole number as necessary. Initial population size: fish Population size after 8 years: fish

Evaluating an exponential function with base e that models a real-world...

A species of fish was added to a lake. The population size P(t) of this species can be modeled by the following function, where t is the number of years from the time the species was added to the lake.

P(t) = 1200 / (1 + 2 e^(-0.3 t))

Find the initial population size of the species and the population size after 8 years. Round your answers to the nearest whole number as necessary.

Initial population size: fish

Population size after 8 years: fish
Transcript text: Evaluating an exponential function with base e that models a real-world... A species of fish was added to a lake. The population size $P(t)$ of this species can be modeled by the following function, where $t$ is the number of years from the time the species was added to the lake. \[ P(t)=\frac{1200}{1+2 e^{-0.3 t}} \] Find the initial population size of the species and the population size after 8 years. Round your answers to the nearest whole number as necessary. Initial population size: fish Population size after 8 years: $\square$ fish
failed

Solution

failed
failed

Solution Steps

To find the initial population size, evaluate the function P(t) P(t) at t=0 t = 0 . For the population size after 8 years, evaluate the function at t=8 t = 8 . Use Python to compute these values and round the results to the nearest whole number.

Step 1: Initial Population Size

To find the initial population size, we evaluate the function P(t) P(t) at t=0 t = 0 : P(0)=12001+2e0.30=12001+21=12003=400 P(0) = \frac{1200}{1 + 2 e^{-0.3 \cdot 0}} = \frac{1200}{1 + 2 \cdot 1} = \frac{1200}{3} = 400 Thus, the initial population size is 400 400 fish.

Step 2: Population Size After 8 Years

Next, we evaluate the function P(t) P(t) at t=8 t = 8 : P(8)=12001+2e0.38=12001+2e2.4 P(8) = \frac{1200}{1 + 2 e^{-0.3 \cdot 8}} = \frac{1200}{1 + 2 e^{-2.4}} Calculating e2.4 e^{-2.4} gives approximately 0.090717953 0.090717953 : P(8)=12001+20.090717953=12001+0.181435906=12001.1814359061016 P(8) = \frac{1200}{1 + 2 \cdot 0.090717953} = \frac{1200}{1 + 0.181435906} = \frac{1200}{1.181435906} \approx 1016 Thus, the population size after 8 years is 1016 1016 fish.

Final Answer

The initial population size is 400 400 fish and the population size after 8 years is 1016 1016 fish. Therefore, the answers are: 400 fish \boxed{400 \text{ fish}} 1016 fish \boxed{1016 \text{ fish}}

Was this solution helpful?
failed
Unhelpful
failed
Helpful