Questions: Solve the system algebraically.
23. -2x - y = -14
3x - y = 11
a. (-4, -5)
c. (-5, -4)
b. (5, 4)
d. (4, 5)
Transcript text: Solve the system algebraically.
23. $\left\{\begin{array}{l}-2 x-y=-14 \\ 3 x-y=11\end{array}\right.$
a. $(-4,-5)$
c. $(-5,-4)$
b. $(5,4)$
d. $(4,5)$
Solution
Solution Steps
Step 1: Write down the system of equations
The given system of equations is:
\[
\begin{cases}
-2x - y = -14 \\
3x - y = 11
\end{cases}
\]
Step 2: Subtract the first equation from the second to eliminate \( y \)
Subtract the first equation from the second:
\[
(3x - y) - (-2x - y) = 11 - (-14)
\]
Simplify:
\[
3x - y + 2x + y = 11 + 14
\]
\[
5x = 25
\]
Step 3: Solve for \( x \)
Divide both sides by 5:
\[
x = \frac{25}{5} = 5
\]
Step 4: Substitute \( x = 5 \) into the first equation to solve for \( y \)
Substitute \( x = 5 \) into the first equation:
\[
-2(5) - y = -14
\]
Simplify:
\[
-10 - y = -14
\]
Add 10 to both sides:
\[
-y = -4
\]
Multiply both sides by -1:
\[
y = 4
\]
Step 5: Verify the solution
The solution is \( (5, 4) \), which corresponds to option b.