Questions: Jack needs to hire someone to feed and walk his dogs while he is away on a business trip. His neighbor said that she can do it for 40 per day. He also found a pet-sitting company that charges 25 per day, plus a 75 registration fee.
Which equation can you use to find d, the number of days the trip would need to last for the two options to cost the same?
40d=25d+75
How many days would the trip need to last for the two options to cost the same?
days
Transcript text: Jack needs to hire someone to feed and walk his dogs while he is away on a business trip. His neighbor said that she can do it for $40 per day. He also found a pet-sitting company that charges $25 per day, plus a $75 registration fee.
Which equation can you use to find $d$, the number of days the trip would need to last for the two options to cost the same?
$40 d=25 d+75$
How many days would the trip need to last for the two options to cost the same?
$\square$ days
Solution
Solution Steps
To find the number of days \( d \) for which the cost of hiring the neighbor and the pet-sitting company are the same, we need to set up an equation where the total cost for both options is equal. The neighbor charges $40 per day, so the cost is \( 40d \). The pet-sitting company charges $25 per day plus a $75 registration fee, so the cost is \( 25d + 75 \). We set these two expressions equal to each other and solve for \( d \).
Step 1: Set Up the Equation
To find the number of days \( d \) for which the costs of hiring the neighbor and the pet-sitting company are equal, we set up the equation based on their costs:
\[
40d = 25d + 75
\]
Step 2: Solve the Equation
We can simplify the equation by isolating \( d \):
\[
40d - 25d = 75
\]
This simplifies to:
\[
15d = 75
\]
Dividing both sides by 15 gives:
\[
d = 5
\]
Final Answer
The number of days the trip would need to last for the two options to cost the same is \\(\boxed{5}\\).