Questions: Jack needs to hire someone to feed and walk his dogs while he is away on a business trip. His neighbor said that she can do it for 40 per day. He also found a pet-sitting company that charges 25 per day, plus a 75 registration fee. Which equation can you use to find d, the number of days the trip would need to last for the two options to cost the same? 40d=25d+75 How many days would the trip need to last for the two options to cost the same? days

Jack needs to hire someone to feed and walk his dogs while he is away on a business trip. His neighbor said that she can do it for 40 per day. He also found a pet-sitting company that charges 25 per day, plus a 75 registration fee.
Which equation can you use to find d, the number of days the trip would need to last for the two options to cost the same?
40d=25d+75

How many days would the trip need to last for the two options to cost the same?
days
Transcript text: Jack needs to hire someone to feed and walk his dogs while he is away on a business trip. His neighbor said that she can do it for $40 per day. He also found a pet-sitting company that charges $25 per day, plus a $75 registration fee. Which equation can you use to find $d$, the number of days the trip would need to last for the two options to cost the same? $40 d=25 d+75$ How many days would the trip need to last for the two options to cost the same? $\square$ days
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Solution

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Solution Steps

To find the number of days \( d \) for which the cost of hiring the neighbor and the pet-sitting company are the same, we need to set up an equation where the total cost for both options is equal. The neighbor charges $40 per day, so the cost is \( 40d \). The pet-sitting company charges $25 per day plus a $75 registration fee, so the cost is \( 25d + 75 \). We set these two expressions equal to each other and solve for \( d \).

Step 1: Set Up the Equation

To find the number of days \( d \) for which the costs of hiring the neighbor and the pet-sitting company are equal, we set up the equation based on their costs: \[ 40d = 25d + 75 \]

Step 2: Solve the Equation

We can simplify the equation by isolating \( d \): \[ 40d - 25d = 75 \] This simplifies to: \[ 15d = 75 \] Dividing both sides by 15 gives: \[ d = 5 \]

Final Answer

The number of days the trip would need to last for the two options to cost the same is \\(\boxed{5}\\).

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