Questions: In planning her retirement, Liza deposits some money at 1.5% interest, with twice as much deposited at 2%. Find the amount deposited at each rate if the total annual interest income is 825.
She deposited at 1.5% and at 2%
Transcript text: In planning her retirement, Liza deposits some money at $1.5 \%$ interest, with twice as much deposited at $2 \%$. Find the amount deposited at each rate if the total annual interest income is $\$ 825$.
She deposited $\$$ $\square$ at $1.5 \%$ and $\$$ $\square$ at $2 \%$
Solution
Solution Steps
To solve this problem, we need to set up a system of linear equations based on the given information. Let \( x \) be the amount deposited at 1.5% interest and \( y \) be the amount deposited at 2% interest. We know that the total interest income is $825. We also know that twice as much is deposited at 2% as at 1.5%. This gives us two equations:
\( 0.015x + 0.02y = 825 \)
\( y = 2x \)
We can solve these equations simultaneously to find the values of \( x \) and \( y \).
Step 1: Define Variables and Equations
Let \( x \) be the amount deposited at \( 1.5\% \) interest and \( y \) be the amount deposited at \( 2\% \) interest. We are given the following information:
The total annual interest income is \( \$825 \).
Twice as much is deposited at \( 2\% \) as at \( 1.5\% \).
This gives us the following system of equations:
\[
0.015x + 0.02y = 825
\]
\[
y = 2x
\]
Step 2: Substitute and Solve
Substitute \( y = 2x \) into the first equation:
\[
0.015x + 0.02(2x) = 825
\]
\[
0.015x + 0.04x = 825
\]
\[
0.055x = 825
\]
\[
x = \frac{825}{0.055} = 15000
\]
Step 3: Calculate \( y \)
Using \( y = 2x \):
\[
y = 2 \times 15000 = 30000
\]
Final Answer
Liza deposited \( \$15000 \) at \( 1.5\% \) and \( \$30000 \) at \( 2\% \).