Questions: 7x^2-31x-20 7x^2-31x-20(x-4)(x-5) 20 div 2

7x^2-31x-20
7x^2-31x-20(x-4)(x-5)
20 div 2
Transcript text: 7 x^{2}-31 x-20 \\ 7 x^{2}-31 x-20(x-4)(x-5) \\ 20 \div 2
failed

Solution

failed
failed

Solution Steps

Solution Approach
  1. Factor the quadratic equation \(7x^2 - 31x - 20\).
  2. Verify the factorization by expanding the factors.
  3. Perform the division \(20 \div 2\).
Step 1: Factor the Quadratic Equation

Given the quadratic equation: \[ 7x^2 - 31x - 20 \]

The factors of the quadratic equation are: \[ (x - 5)(7x + 4) \]

Step 2: Verify the Factorization

To verify, we expand the factors: \[ (x - 5)(7x + 4) = 7x^2 - 31x - 20 \]

The expanded expression matches the original quadratic equation, confirming the factorization is correct.

Step 3: Perform the Division

Perform the division: \[ 20 \div 2 = 10.0 \]

Final Answer

\(\boxed{(x - 5)(7x + 4)}\)

Was this solution helpful?
failed
Unhelpful
failed
Helpful