Questions: Rewrite this equation using telescoping methods:
H=4-(7/(4-(7/(4-(7/(4-(7/...)))))))
Read Example 3.
H=7+(H/4)
H=4+(7/H)
H=7-(4/H)
H=4-(7/H)
Transcript text: Rewrite this equation using telescoping methods:
\[
H=4-\frac{7}{4-\frac{7}{4-\frac{7}{4-\frac{7}{4-\ldots}}}}
\]
Read Example 3.
$H=7+\frac{H}{4}$
$H=4+\frac{7}{H}$
$H=7-\frac{4}{H}$
$H=4-\frac{7}{H}$
Solution
Solution Steps
To rewrite the given equation using telescoping methods, we need to recognize the pattern in the continued fraction and express it in a simpler form. We can set up an equation where \( H \) is equal to the continued fraction and solve for \( H \).
Step 1: Set Up the Equation
We start by setting up the equation based on the given continued fraction:
\[
H = 4 - \frac{7}{4 - \frac{7}{4 - \frac{7}{4 - \ldots}}}
\]
We can express this as:
\[
H = 4 - \frac{7}{4 - \frac{7}{H}}
\]
Step 2: Solve the Equation
To solve for \( H \), we rearrange the equation:
\[
H = 4 - \frac{7}{4 - \frac{7}{H}}
\]
Multiplying both sides by \( H \) to eliminate the fraction, we get:
\[
H \left(4 - \frac{7}{H}\right) = 4H - 7
\]
Simplifying, we obtain:
\[
H^2 = 4H - 7
\]
Rearranging terms, we get a quadratic equation:
\[
H^2 - 4H + 7 = 0
\]
Step 3: Solve the Quadratic Equation
We solve the quadratic equation \( H^2 - 4H + 7 = 0 \) using the quadratic formula:
\[
H = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]
where \( a = 1 \), \( b = -4 \), and \( c = 7 \). Plugging in these values, we get:
\[
H = \frac{4 \pm \sqrt{16 - 28}}{2}
\]
\[
H = \frac{4 \pm \sqrt{-12}}{2}
\]
\[
H = \frac{4 \pm 2i\sqrt{3}}{2}
\]
\[
H = 2 \pm i\sqrt{3}
\]