Questions: The molecular geometry of ClO4- is The molecular geometry of BrO2- is The molecular geometry of NO2- is The molecular geometry of SO4^2- is

The molecular geometry of ClO4- is 
The molecular geometry of BrO2- is 
The molecular geometry of NO2- is 
The molecular geometry of SO4^2- is
Transcript text: The molecular geometry of $\mathrm{ClO}_{4}{ }^{-}$is $\square$ The molecular geometry of $\mathrm{BrO}_{2}{ }^{-}$is $\square$ The molecular geometry of $\mathrm{NO}_{2}{ }^{-}$is $\square$ The molecular geometry of $\mathrm{SO}_{4}{ }^{2-}$ is $\square$
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Solution

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Solution Steps

Step 1: Determine the Lewis Structure

To determine the molecular geometry, we first need to draw the Lewis structures of the given ions.

Step 2: Apply VSEPR Theory

Using the Valence Shell Electron Pair Repulsion (VSEPR) theory, we can predict the molecular geometry based on the number of bonding pairs and lone pairs around the central atom.

Step 3: Determine the Molecular Geometry
  1. $\mathrm{ClO}_{4}^{-}$:

    • Central atom: Cl
    • Total valence electrons: \(7 + 4 \times 6 + 1 = 32\)
    • Lewis structure: Cl is bonded to four O atoms with no lone pairs on Cl.
    • Geometry: Tetrahedral
  2. $\mathrm{BrO}_{2}^{-}$:

    • Central atom: Br
    • Total valence electrons: \(7 + 2 \times 6 + 1 = 20\)
    • Lewis structure: Br is bonded to two O atoms with two lone pairs on Br.
    • Geometry: Bent (or V-shaped)
  3. $\mathrm{NO}_{2}^{-}$:

    • Central atom: N
    • Total valence electrons: \(5 + 2 \times 6 + 1 = 18\)
    • Lewis structure: N is bonded to two O atoms with one lone pair on N.
    • Geometry: Bent (or V-shaped)

Final Answer

\[ \begin{aligned} &\text{The molecular geometry of } \mathrm{ClO}_{4}^{-} \text{ is } \boxed{\text{tetrahedral}}. \\ &\text{The molecular geometry of } \mathrm{BrO}_{2}^{-} \text{ is } \boxed{\text{bent}}. \\ &\text{The molecular geometry of } \mathrm{NO}_{2}^{-} \text{ is } \boxed{\text{bent}}. \\ \end{aligned} \]

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