We are given the binomial \( y^{3} - 27 \). This expression can be recognized as a difference of cubes, since \( 27 \) can be expressed as \( 3^3 \).
Step 2: Apply the Difference of Cubes Formula
The difference of cubes can be factored using the formula:
\[
a^3 - b^3 = (a - b)(a^2 + ab + b^2)
\]
In our case, let \( a = y \) and \( b = 3 \). Thus, we can rewrite the expression as:
\[
y^{3} - 3^{3}
\]
Step 3: Factor the Expression
Applying the difference of cubes formula, we have:
\[
y^{3} - 27 = (y - 3)(y^{2} + 3y + 9)
\]
Final Answer
The factorized form of the polynomial \( y^{3} - 27 \) is:
\[
\boxed{(y - 3)(y^{2} + 3y + 9)}
\]