Questions: A ball is thrown from an initial height of 2 feet with an initial upward velocity of 17 ft/s. The ball's height h (in feet) after t seconds is given by the following: h = -16t^2 + 17t + 2 Find all values of t for which the ball's height is 6 feet. (If there is more than one answer, use the "or" button.) t = (17 ± sqrt(17^2 - 4(-16)(2-6)))/(2(-16)) = (17 ± sqrt(289 + 256))/(-32) = (17 ± sqrt(545))/(-32) Round your answer(s) to the nearest hundredth. seconds

A ball is thrown from an initial height of 2 feet with an initial upward velocity of 17 ft/s. The ball's height h (in feet) after t seconds is given by the following:

h = -16t^2 + 17t + 2

Find all values of t for which the ball's height is 6 feet.

(If there is more than one answer, use the "or" button.)

t = (17 ± sqrt(17^2 - 4(-16)(2-6)))/(2(-16)) = (17 ± sqrt(289 + 256))/(-32) = (17 ± sqrt(545))/(-32)

Round your answer(s) to the nearest hundredth.

seconds

Transcript text: A ball is thrown from an initial height of 2 feet with an initial upward velocity of 17 ft/s. The ball's height h (in feet) after t seconds is given by the following: h = -16t^2 + 17t + 2 Find all values of t for which the ball's height is 6 feet. (If there is more than one answer, use the "or" button.) t = \frac{17 \pm \sqrt{17^2 - 4(-16)(2-6)}}{2(-16)} = \frac{17 \pm \sqrt{289 + 256}}{-32} = \frac{17 \pm \sqrt{545}}{-32} Round your answer(s) to the nearest hundredth. seconds