Questions: What is the product of the 2 x^3 and the 4 x^2 y-3 x y^2 ?
a.) 8 x^5 y-6 x^4 y^2
b.) 8 x^5 y-3 x y^2
c.) 8 x^6 y-6 x^3 y^2
d.) 8 x^6 y-3 x y^2
Transcript text: What is the product of the $2 x^{3}$ and the $4 x^{2} y-3 x y^{2} ?$
a.) $8 x^{5} y-6 x^{4} y^{2}$
b.) $8 x^{5} y-3 x y^{2}$
c.) $8 x^{6} y-6 x^{3} y^{2}$
d.) $8 x^{6} y-3 x y^{2}$
Solution
Solution Steps
To find the product of a monomial and a binomial, we need to distribute the monomial to each term in the binomial. Specifically, we will multiply \(2x^3\) by each term in the binomial \(4x^2y - 3xy^2\).
Step 1: Define the Monomial and Binomial
We start with the monomial \(2x^3\) and the binomial \(4x^2y - 3xy^2\).
Step 2: Distribute the Monomial
We will distribute the monomial \(2x^3\) to each term in the binomial:
\[
2x^3 \cdot (4x^2y) \quad \text{and} \quad 2x^3 \cdot (-3xy^2)
\]
Step 3: Calculate Each Product
Calculating the first term:
\[
2x^3 \cdot 4x^2y = 8x^{5}y
\]
Calculating the second term:
\[
2x^3 \cdot (-3xy^2) = -6x^{4}y^{2}
\]
Step 4: Combine the Results
Now, we combine the results from the two products:
\[
8x^{5}y - 6x^{4}y^{2}
\]
Final Answer
The product of the monomial and the binomial is:
\[
\boxed{8x^{5}y - 6x^{4}y^{2}}
\]